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andriy [413]
2 years ago
8

Where can the perpendicular bisectors of an obtuse triangle intersect

Mathematics
1 answer:
Flura [38]2 years ago
3 0
The answer for this question is incenter
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A baseball team wins one out of every three games. How many wins<br> would they have after 27 games?
Darina [25.2K]

Answer:

9 wins

Step-by-step explanation:

\frac{1}{3} =\frac{x}{27} \\\\3x=27\\x=9

They'd have 9 wins after 27 games.

8 0
3 years ago
I need your help pls
Zielflug [23.3K]

Answer:

1. Let the number is x

a) 8 more than 4 times a number is 28

<u>Required equation:</u>

  • 4x + 8 = 28

b) <u>Example would be:</u>

Four teams of same number of members joined together and the team of eight joined them adding up to 28 people.

3.

  • Height - h, length - l
  • h = 1/3l
  • h = 5 feet, l = ?

    ----

  • l = 3h
  • l = 3*5 = 15 feet

8.

<u>Equation:</u>

  • 6a - 16 = b

<u>Example situation:</u>

6 packs of each containing a number of items. It was reduced by 16 (sold) and b number of items left in the stock.

<u><em /></u>

<u><em>Note</em></u>. <em>You need to add your details to the examples.</em>

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8 0
2 years ago
Please help pre algebra it’s super hard
Rzqust [24]

Answer:

a reflection and then a translation

a translation and then a rotation

a rotation and then a reflection

Hope this helps

7 0
3 years ago
The numbers 0.23350 has how many significant figures?
Alenkinab [10]

Significant figures are the digits that carry meaning to its measurement. Significant figures includes all the numbers excluding all the leading zeros, trailing zeros. All non zero digits are significant. Zeros between the non zero digits are significant. In a decimal number, trailing zeros are significant.

Now, consider the given number 0.23350

Since, in a decimal number all the trailing zeros are significant.

So, in the number 0.23350 there are five significant figures 2,3,4,5 and 0.

Therefore, there are 5 significant figures in the given number.

3 0
3 years ago
Read 2 more answers
Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)
finlep [7]
The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0
3 years ago
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