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andriy [413]
2 years ago
8

Where can the perpendicular bisectors of an obtuse triangle intersect

Mathematics
1 answer:
Flura [38]2 years ago
3 0
The answer for this question is incenter
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What is the slope of a line that is perpendicular to the line x=-3?
jonny [76]
Perpendicular = Negative Reciprocal

-3 --> -1/3 ---> 1/3

Therefore it is C
7 0
3 years ago
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What is 4 wholes and 49 over 100 in decimal form
SVETLANKA909090 [29]
49/100 is equal to .49 in decimal form, and now we just need to add the 4 wholes.  This is equal to 4.49
5 0
3 years ago
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Hey can you please help me posted picture of question
zhuklara [117]
For this case we have the following polynomial:
 x2 + 6x + 8
 We note that the polynomial can be rewritten as:
 (x + 4) (x + 2)
 Answer:
 
A common factor binomial for this case is given by:
 
(x + 4)
 
option B
7 0
2 years ago
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Find m angle TUV if m angle TUN=1+38 pi m angle NUV=66^ m angle TUV=105x
ipn [44]

Answer:

m∠TUV = 105

Step-by-step explanation:

From the question given above, the following data were obtained:

m∠TUN = 1 + 38x

m∠NUV = 66°

m∠TUV = 105x

m∠TUV =?

Next, we shall determine the value of x. This can be obtained as illustrated below:

m∠TUV = m∠TUN + m∠NUV

105x = (1 + 38x) + 66

105x = 1 + 38x + 66

Collect like terms

105x – 38x = 1 + 66

67x = 67

Divide both side by 67

x = 67 / 67

x = 1

Finally, we shall determine the value of m∠TUV. This can be obtained as shown below:

m∠TUV = 105x

x = 1

m∠TUV = 105(1)

m∠TUV = 105

5 0
3 years ago
6) the circular base of a hemisphere of radius 2 rests on the base of a square pyramid of height 6. the hemisphere is tangent to
Rasek [7]

The length of the square base is thus 2 x 3\sqrt{2}/2 = 3\sqrt{2} = A

<h3>What is hemisphere?</h3>

Consequently, a hemisphere is a 3D geometric object that is made up of half of a sphere, with one side being flat and the other being a bowl-like shape. It is created by precisely cutting a spherical along its diameter, leaving behind two identical hemispheres.

EXPLANATION; Let ABCDE be the pyramid with ABCD as the square base. Let O and M be the center of square ABCD and the midpoint of side AB respectively. Lastly, let the hemisphere be tangent to the triangular face ABE at P.

Notice that triangle EOM has a right angle at O. Since the hemisphere is tangent to the triangular face ABE at P, angle EPO is also 90 degree. Hence, triangle EOM is similar to triangle EPO.

OM/2 = 6/EP

OM = 6/EP x 2

OM = 6\sqrt{6^2 - 2^2} x 2 = 3\sqrt{2}/2}

The length of the square base is thus 2 x 3\sqrt{2}/2 = 3\sqrt{2} = A

To know more about Hemisphere, visit;

brainly.com/question/13625065?referrer=searchResults

#SPJ4

6 0
1 year ago
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