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trasher [3.6K]
3 years ago
10

Based on the given inequality statement, which statement correctly describes where the values are located on a number line rela

to each other? -5 < 2 © 2 is located at the same position as -5. 5 is located to the left of 2. 2 is located to the left of -5. 0-5 is located to the right of 2.​
Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

what are the different choices?

Step-by-step explanation:

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Find the general solution of the following equation: y'(t) = 3y -5
Anton [14]

Answer:

The general solution of the equation is y = \frac{A}{3}e^{3t} + 5

Step-by-step explanation:

Since the differential equation is given as y'(t) = 3y -5

The differential equation is re-written as

dy/dt = 3y - 5

separating the variables, we have

dy/(3y - 5) = dt

dy/(3y - 5) = dt

integrating both sides, we have

∫dy/(3y - 5) = ∫dt

∫3dy/[3(3y - 5)] = ∫dt

(1/3)∫3dy/(3y - 5) = ∫dt

(1/3)㏑(3y - 5) = t + C

㏑(3y - 5) = 3t + 3C

taking exponents of both sides, we have

exp[㏑(3y - 5)] = exp(3t + 3C)

3y - 5 = e^{3t}e^{3C}        

3y - 5 = Ae^{3t}                A = e^{3C}

3y = Ae^{3t} + 5    

dividing through by 3, we have

y = \frac{A}{3}e^{3t} + 5

So, the general solution of the equation is y = \frac{A}{3}e^{3t} + 5

3 0
4 years ago
Can someone help me please
Yuliya22 [10]

Answer:

B

Step-by-step explanation:


3 0
3 years ago
What is the area of the parallelogram
ololo11 [35]
Multiply all to find the area of any
7 0
3 years ago
Sylvie finds the solution to the system of equations by graphing. y = x + 1 and y = x – 1 Which graph shows the solution to Sylv
Alexeev081 [22]
The only solution is when y=y

x+1=x-1  subtract x from both sides

1=-1

This is never true so there are no solutions.  In this case it is due to the fact that both lines have the same slope and different y-intercepts.  This means that they are parallel lines that have a constant distance between them.
5 0
4 years ago
What is the length of the line segment with endpoints (7,-1) and (-3,5)?
Galina-37 [17]

Formula to find the length of two endpoints: \sqrt{(x^2-x^1)^2+(y^2-y^1)^2}

Now, solve with the given endpoints.

\sqrt{(x^2-x^1)^2+(y^2-y^1)^2} \\\sqrt{(-3-7)^2+(5-(-1))^2} \\\sqrt{(-10)^2 + (6)^2} \\ \sqrt{100+36}\\\sqrt{136}

_______

Now, simplify using what we know about radicals.

Solution in picture.

_______

The length between the endpoints is 2√34 (Option B)

_______

Best Regards,

Wolfyy :)

8 0
3 years ago
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