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schepotkina [342]
3 years ago
7

Find all real solutions of this equation to answer

Mathematics
2 answers:
Gekata [30.6K]3 years ago
7 0

Answer:

The answer is C.

Step-by-step explanation:

Edge2020

Lera25 [3.4K]3 years ago
6 0

Answer:

(6-2x)(3-2x)x=40

Step-by-step explanation:

(-2x-2x) (6+3)x=40

8x=40

8x/8=40/8

x=5

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J/2--12=15 <br> j/2 is a fraction
Natasha_Volkova [10]

Answer:

j = 54

Step-by-step explanation:

j/2 - 12 = 15

j/2 = 15 +12

j/2 *2  = 27 * 2

j = 54

If you're kind enough, please mark this as the brainlist answer!

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Quiz of the day whoever answer will be marked as brainliest
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If e^9xe^2xe^-8=e^x what is the value of x
Inessa [10]

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3 years ago
What is the solution to e/10&gt;12.50
mrs_skeptik [129]

Answer:

e > 125

Step-by-step explanation:

Given

\frac{e}{10} > 12.50

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8 0
3 years ago
What is (4x+-7)(2x+-9)
uysha [10]

Answer:x=1

Step-by-step explanation:(4x+-7)=(2x+-9)

We move all terms to the left:

(4x+-7)-((2x+-9))=0

We add all the numbers together, and all the variables

(4x-7)-((2x-9))=0

We get rid of parentheses

4x-((2x-9))-7=0

We calculate terms in parentheses: -((2x-9)), so:

(2x-9)

We get rid of parentheses

2x-9

Back to the equation:

-(2x-9)

We get rid of parentheses

4x-2x+9-7=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

(4x+-7)=(2x+-9)

We move all terms to the left:

(4x+-7)-((2x+-9))=0

We add all the numbers together, and all the variables

(4x-7)-((2x-9))=0

We get rid of parentheses

4x-((2x-9))-7=0

We calculate terms in parentheses: -((2x-9)), so:

(2x-9)

We get rid of parentheses

2x-9

Back to the equation:

-(2x-9)

We get rid of parentheses

4x-2x+9-7=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

8 0
3 years ago
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