This is based on my assumption that brown is dominant over blue.
Since both parent have parents who are homo_zygous recessive, this tells us that both parents will be hetero_zygous.
When you cross two hetero_zygous parents, it can produce these genotypic and phenotypic ratios:
<u>Genotypic</u>
BB : Bb : bb
1 : 2 : 1
<u>Phenotypic</u>
brown : blue
3 : 1
Therefore there is a 75% chance that they will produce a brown-eyed offspring.
Usually if they have chloroplasts, they’re autotrophic. If they don’t have chloroplasts then they’re autotrophic, although members of Excavata like euglenozoans can be mixotrophic
They're converted to 'Acetyl- CoA'
Hope this helps
It’s pretty nice but you gotta be really smart for that job but if your going good luck!! :)
Answer:
Option D
Explanation:
Cyanobacteria preserve its photosynthetic pigments in the thylakoids which allows masking of green of chlorophyll a and other accessory pigment i.e phycobiliproteins (phycocyanin, allophycocyanin and phycoerythrin).
Chlorophyll a is mainly responsible for harvesting light for photosynthesis. Phycocyanin is blue in color, allophycocyanin is blue in color and phycoerythrine is red in color. These together harvest light in the green, yellow and orange part of the spectrum which cannot be used by other phytoplankton species
Hence, option D is correct
