Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
Turn them both into mixed fractions and voila
From the first 2 statements again , x + 8 = y.
area of the hole would be 4x cm^2
area of sheet without hole is 9y cm^2
9y - 4x =76 ------------- eqn one
y = x + 8 ----------------eqn two
subs eqn two into one and u got it
btw what questions are these :o
Answer:
-8m +24 -32n
Step-by-step explanation:
(m-3+4n)*(-8)
Distribute the -8 to each term inside the parentheses
-8*m -8*-3 -8*4n
-8m +24 -32n
