A) square feet
if you are measuring the room u do not use centimeters because it to small to measure and take forever to measure the room
mile are long so that won't work
inches take a long time to measure a room that would not work
so a is the answer

3 0

4 years ago

A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of the triangle? Round your answer to the

larisa86 [58]

Use the distance formula to find the length of the sides, then add them up to find the perimeter.

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points in the form of (x1, y1), (x2, y2).

(-1, 2), (3, 1)

$\sf d=\sqrt{(3+1)^2+(1-2)^2}$

$\sf d=\sqrt{(4)^2+(-1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(3, 1), (7, 2)

$\sf d=\sqrt{(7-3)^2+(2-1)^2}$

$\sf d=\sqrt{(4)^2+(1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(7, 2), (-1, 2)

$\sf d=\sqrt{(-1-7)^2+(2-2)^2}$

$\sf d=\sqrt{(-8)^2+(0)^2}$

$\sf d=\sqrt{64+0}$

$\sf d=\sqrt{64}=8$

So the perimeter will be:

$\sf 8+\sqrt{17}+\sqrt{17}\approx\boxed{\sf 16.25}$

3 0

4 years ago

What is the derivative of x^3?

WITCHER [35]

Answer:

$3x^{2}$

Step-by-step explanation:

5 0

3 years ago

Which set of parametric equations describes a line that passes through the points (0,0) and (4,8) ?

ale4655 [162]

Answer:

The correct option is A)

Step-by-step explanation:

To find the correct equation we first need to calculate the angular coefficient for the line, with the formula below:

m = (y2 - y1)/(x2 - x1)

m = (8 - 0)/(4 - 0) = 8/4 = 2

Using that we can apply to the equation of the line:

y = m*x + c

Since the line pass through (0,0) c must be equal to 0, so:

y = m*x

y = 2*x

So x must be:

x = t.

8 0

3 years ago