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GarryVolchara [31]
4 years ago
10

Cot(pi/2)=1-1undefined0

Mathematics
2 answers:
devlian [24]4 years ago
6 0

Answer:

Option D

Step-by-step explanation:

We have to find the value of cot (\frac{\pi}{2})

Since cot θ = \frac{1}{tan\theta}

and θ = \frac{\pi}{2}

So cotcot(\frac{\pi}{2})=\frac{1}{tan(\frac{\pi}{2})}

                    = \frac{1}{(\frac{1}{0})}

                    = 0

Therefore, answer will be option D), 0.

GenaCL600 [577]4 years ago
4 0

Answer:

the answer is zeroo

Step-by-step explanation:


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-4(9-3x)=0

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neon: 0 percent change    oxide: -2 percent change   copper: 2 percent change   tin: 0 percent change

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Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti
alukav5142 [94]

Answer:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Step-by-step explanation:

We want to evaluate the limit:

\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}

To do so, we can divide everything by <em>x</em>². So:

=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}

Now, we can apply direct substitution:

\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}

Any constant value over infinity tends towards 0. Therefore:

\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3

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\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3<em>x</em>²<em>, </em>and in the denominator it is <em>x</em>². So:

\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}

Simplify:

\displaystyle =\lim_{x\to\infty}3=3

The limit of a constant is simply the constant.

We acquire the same answer.

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