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4 years ago

Cot(pi/2)=1-1undefined0

Mathematics

2 answers:

devlian [24]4 years ago

6 0

Answer:

Option D

Step-by-step explanation:

We have to find the value of cot $(\frac{\pi}{2})$

Since cot θ = $\frac{1}{tan\theta}$

and θ = $\frac{\pi}{2}$

So cot $cot(\frac{\pi}{2})=\frac{1}{tan(\frac{\pi}{2})}$

= $\frac{1}{(\frac{1}{0})}$

= 0

Therefore, answer will be option D), 0.

GenaCL600 [577]4 years ago

4 0

Answer:

the answer is zeroo

Step-by-step explanation:

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KATRIN_1 [288]

Answer:

Step-by-step explanation:

-4(9-3x)=0

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3 years ago

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2 years ago

16/9 is equal to 2 times which fraction?

xxTIMURxx [149]

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3 years ago

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Evaluate the indicated limit algebraically. Change the form of the function where necessary. Please write clearly with descripti

alukav5142 [94]

Answer:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3$

Step-by-step explanation:

We want to evaluate the limit:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}$

To do so, we can divide everything by x². So:

$=\displaystyle \lim_{x\to \infty}\frac{3+4.5/x^2}{1-1.5/x^2}$

Now, we can apply direct substitution:

$\Rightarrow \displaystyle \frac{3+4.5/(\infty)^2}{1-1.5/(\infty)^2}$

Any constant value over infinity tends towards 0. Therefore:

$\displaystyle =\frac{3+0}{1+0}=\frac{3}{1}=3$

Hence:

$\displaystyle \lim_{x\to \infty}\frac{3x^2+4.5}{x^2-1.5}=3$

Alternatively, we can simply consider the biggest term of the numerator and the denominator. The term with the strongest influence in the numerator is 3x², and in the denominator it is x². So:

$\displaystyle \Rightarrow \lim_{x\to\infty}\frac{3x^2}{x^2}$

Simplify:

$\displaystyle =\lim_{x\to\infty}3=3$

The limit of a constant is simply the constant.

We acquire the same answer.

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3 years ago