You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
It's 16 units. Just look at the lengths and how many times they are on a shape. The shape is a rectangle, which means there will be two of each length, so just add them all together. 6+6+2+2=16
.2 (simplified from 0.20)
2/10 (simplified from 20/100)
I am rocking with C. Jasmine left class for head.
if im wrong let me know
Answer:
Step-by-step explanation: 1 foot= 12 inches
so length 5.5 inches= 0.458 feet or 5.5/12
width 4 inches= 0.33 feet or 4/12
area 4x5.5= 1.833 feet or 22/12
