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maria [59]
3 years ago
10

Part A: What is the group of points labeled P called? What is the point labeled T called? Give a possible reason for the presen

ce of point T.
Part B: Describe the association between students' test scores and the number of hours they exercise.

Mathematics
1 answer:
levacccp [35]3 years ago
7 0
Labeled p is cluster point t is an outlier
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The product 33 × 90 is more than 32 × 90. How much more? Complete the explanation for how you know without multiplying.
Tju [1.3M]

Answer:

90, there are 32 ninetys in 32 X 90 and there are 33 ninetys in 33 X 90, meaning there is one more 90 in 33 X 90 than 32 X 90

5 0
2 years ago
A farmer wants to build a fence enclosing a rectangular region bordering a river. If the farmer has 500 feet of fencing, find th
Romashka [77]

Answer:

31,250 ft²

Step-by-step explanation:

Let x represent the length of fence parallel to the river. Then the ends of the rectangle will have dimesion (500-x)/2, and the total area will be ...

... A = x(500-x)/2

This function describes a parabola with zeros at x=0 and x=500. The vertex (maximum) will be located halfway between these, at x=250.

The maximum size pen has area ...

... A = 250(500 -250)/2 = 31,250 . . . . sq ft

4 0
3 years ago
Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69
Elena L [17]
If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}
3 0
3 years ago
Subject differential equation<br>Day. Month.<br>Year. ..<br>(y-secx<br>) dx + tanxdy...o​
Colt1911 [192]

(y-\sec x)\,\mathrm dx+\tan x\,\mathrm dy=0

Divide both side by \mathrm dx and rearrange terms to get a linear ODE;

\tan x\dfrac{\mathrm dy}{\mathrm dx}+y=\sec x

Multiply both sides by \cos x:

\sin x\dfrac{\mathrm dy}{\mathrm dx}+\cos x\,y=1

The left side can be condensed as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dx}(\sin x\,y)=1

Integrate both sides, then solve for y:

\sin x\,y=x+C\implies\boxed{y(x)=x\csc x+C\csc x}

8 0
3 years ago
1-6. Indicate whether each table or graph represents a proportional
Pie

Answer:

Step-by-step explanation:

Proportional relationship means,

x ∝ y

x = ky

\frac{x}{y}=k where 'k' is the proportionality constant.

From table (1),

\frac{1}{5}=\frac{2}{9}\neq  \text{Constant}

Therefore, relationship is not proportional.

From table (2),

\frac{1}{6}=\frac{3}{18}=\text{constant}

True.

So the relationship will be proportional.

From table (3),

\frac{\text{hours}}{\text{Miles}}= \frac{2}{110}=\frac{5}{175}=\frac{1}{55}

Which is constant.

Therefore, relationship will be proportional.

From table (4),

\frac{\text{Hours}}{\text{Paid}}=\frac{3}{29.25}=\frac{5}{48.75}=0.103

Which is constant for every term.

Therefore, relationship will be proportional.

7 0
3 years ago
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