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Mkey [24]
3 years ago
14

Which of the following is the best buy? a 16 oz bag of rice for $2.42 a 12 oz box of rice for $1.93 a 6 oz box of rice for 90¢ a

9 oz box of rice $1.25
Mathematics
2 answers:
stich3 [128]3 years ago
4 0

Answer:

A 9 oz box of rice for $1.25 would be the best buy

Step-by-step explanation:


Temka [501]3 years ago
3 0

For this case we must choose between the four options given, the best purchase in terms of quantity and price of rice.

For this, we get the unit price per ounce of each.

a) \frac {2.42} {16} = 0.15125\\b) \frac {1.93} {12} = 0.16083 \\c) \frac {0.90} {6} = 0.15 \\d) \frac {1.25} {9} = 0.139

So, the best purchase would be:

A 9 oz. Box of rice $ 1.25

Answer:

Option D


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7 more than 6 times a number is negative forty seven what us the number
romanna [79]

Answer:

The number is -9.

Step-by-step explanation:

If we let the number be x we have the equation 6x + 7 = -47.

6x + 7 - 7 = -47 - 7

6x = -54

x = 054/6

x = -9.


3 0
4 years ago
What’s is the value of the expression 7+[8-(1+9)]
Amanda [17]

Answer:

5

Step-by-step explanation:

7+(8-(1+9))

7+(8-10)

7+(-2)

7-2

5

4 0
3 years ago
What answer i need fast
irina [24]

2/3 cup pineapple for every 1/3 cup OJ

 there are three 1/3 cups in 1 cup

 so multiply 2/3 by 3


 2/3 * 3 = 6/3 = 2

 2 cups of pineapple juice is needed


5 0
3 years ago
Complete the square:<br> x2 - 6x + 9=-13+ blank
kvasek [131]

Answer:

to complete the square, you add (b/2)^2  on both side. in this case, b is -6, half of -6 is -3, -3 squared is 9, so:

x^2-6x+9=-13+9

(x-3)^2=-4

This quadratic equation have unreal solutions

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Let f be the function defined as follows:1. If a = 2 and b = 3, is f continuous at x = 1? Justify your answer.2. Find a relation
Arada [10]

Answer:

1. not continuous, as the function definitions deliver different function values at x=1 when approaching this x from the left and from the right side.

2.

2 = a + b

3.

0 = 2a + b

4.

a = -2

b = 4

Step-by-step explanation:

the function is continuous at a specific point or value of x, if the f(x) = y functional value is the same coming from the left and the right side at that point.

1. that means that for x=1

3 - x = ax² + bx

so,

3 - 1 = a×1² + b×1 = a + b

2 = a + b

we have to use a=2 and b=3

2 = 2 + 3 = 5

2 is not equal 5, so the assumed equality is false, so the function is not continuous there.

2. point 1 gave us already the working relationship between a and b.

2 = a + b

only if that is true, is the function continuous at x=1.

3. now for x=2

5x - 10 = ax² + bx

5×2 - 10 = a×2² + b×2 = 4a + 2b

10 - 10 = 4a + 2b

0 = 4a + 2b

0 = 2a + b

4. to find a and b to be continuous at both locations x=1 and x=2 both expressions in a and b must apply.

so, they establish a system of 2 equations with 2 variables.

2 = a + b

0 = 2a + b

a = 2 - b

0 = 2×(2-b) + b = 4 - 2b + b = 4 - b

b = 4

therefore

a = 2 - 4 = -2

5. I cannot draw a graph here.

just use now the function

3 - x, x < 1

‐2x² +4x, 1 <= x < 2

5x - 10, x >= 2

8 0
3 years ago
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