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Tema [17]
3 years ago
15

Select all the expressions that have the same value. 24¹ B) 2⁶ C) 6² D) 2⁵

Mathematics
1 answer:
tester [92]3 years ago
8 0

Answer:

Guess what?

Step-by-step explanation:

None of them have the same value

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Zack bought a coat for $69.78. He paid with $100 bill and received $26.73 in change. How much was the sales tax?
Klio2033 [76]
$3.49

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6 0
3 years ago
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Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
Evaluate<br> 8a-b<br> if a = 10 and b= 6
solniwko [45]

Answer:

74

Step-by-step explanation:

(8x10) - 6 =

80 - 6 = 74

4 0
2 years ago
PLS HELP
Naya [18.7K]
I did the work for you but the answer would be 1 second

5 0
3 years ago
How many unique planes can be determined by four noncoplanar points?
marta [7]

Answer:

Four unique planes

Step-by-step explanation:

Given that the points are non co-planar, triangular planes can be formed by the joining of three points

The points will therefore appear to be at the corners of a triangular pyramid or tetrahedron such that together the four points will form a three dimensional figure bounded by triangular planes

The number of triangular planes that can therefore be formed is given by the combination of four objects taking three at a time as follows;

₄C₃ = 4!/(3!×(4-3)! = 4

Which gives four possible unique planes.

3 0
3 years ago
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