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3 years ago

Select all the expressions that have the same value. 24¹ B) 2⁶ C) 6² D) 2⁵

Mathematics

1 answer:

tester [92]3 years ago

8 0

Answer:

Guess what?

Step-by-step explanation:

None of them have the same value

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Pavel [41]

THE ANSWER SHOULD BE C AND B

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3 years ago

Find the distance between (-6,4) and (-2,1)

zhannawk [14.2K]

Answer:

$d=2.65$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2-(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the formula to find distance <em>d</em>:

$d=\sqrt{(-2-(-6))^2-(1-4)^2}$

$d=\sqrt{(-2+6))^2-(-3)^2}$

$d=\sqrt{(4)^2-9}$

$d=\sqrt{16-9}$

$d=\sqrt{7}$

$d=2.65$

4 0

3 years ago

Can i pls get some help here with how to even solve it using clear steps?

kirill [66]

first off, let's split the triplet into two equations, then from there on we'll do substitution.

$\cfrac{y}{x-z}=\cfrac{x}{y}=\cfrac{x+y}{z}\implies \begin{cases} \cfrac{y}{x-z}=\cfrac{x}{y}\\[2em] \cfrac{x}{y}=\cfrac{x+y}{z} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{\cfrac{y}{x-z}=\cfrac{x}{y}\implies }y^2=\underline{x^2-xz} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 2nd equation}}{\cfrac{x}{y}=\cfrac{x+y}{z}\implies }xz=xy+y^2\implies \stackrel{\textit{substituting for }y^2}{xz=xy+(\underline{x^2-xz})}$

$2xz=xy+x^2\implies 2xz=x(y+x)\implies \cfrac{2xz}{x}=y+x \\\\\\ 2z=y+x\implies 2=\cfrac{y+x}{z}\implies 2=\cfrac{x+y}{z} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{}{ \begin{cases} \cfrac{y}{x-z}=\cfrac{x}{y}\\[2em] \cfrac{x}{y}=\cfrac{x+y}{z} \end{cases}}\implies \begin{cases} \cfrac{y}{x-z}=\cfrac{x}{y}\\[2em] \cfrac{x}{y}=2 \end{cases}\implies \begin{cases} \cfrac{y}{x-z}=2\\[2em] \cfrac{x}{y}=2 \end{cases}$

that of course, is only true if x + y, or our numerator doesn't turn into 0, if it does then our fraction becomes 0 and our equation goes south. Keeping in mind that x,y and z are numeric values that correlate like so.

4 0

2 years ago

What is the maximum height of the basketball when the player passes the ball to someone? Initially, the ball moves at a speed of

ZanzabumX [31]

Answer with explanation:

Since the motion of the ball is projectile motion we shall use the equations for projectile motion.

The maximum height achieved by the projectile is given by

$h_{max}=\frac{v_{o}^{2}sin^{2}(\theta )}{2g}$

Applying the values we get

$h_{max}=\frac{12^{2}\times sin^{2}(45)}{2\times 9.81}\\\\h_{max}=3.669m$

The range of the projectile is given by

$R=\frac{v_{o}^{2}sin(2\theta )}{2g}$

Applying values we get

$R=\frac{12^{2}\times sin(2\times 45 )}{2\times 9.81}\\\\R=7.339m$

thus the maximum horizontal distance reached by the ball equals 7.339 meters after which it bounces thus a person standing 8 meters away will not be able to catch it.

(The height of the players is not taken into account since no info is given about their height.)

3 0

4 years ago

A laptop computer is purchased for $2350. After each year, the resale value decreases by 35% . What will the resale value be aft

pentagon [3]

$\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &2350\\ r=rate\to 35\%\to \frac{35}{100}\dotfill &0.35\\ t=years\dotfill &4\\ \end{cases} \\\\\\ A=2350(1 - 0.035)^{4}\implies A=2350(0.965)^4\implies A\approx 2037.87$

5 0

2 years ago