Step-by-step explanation:
<u>Combine Like-Terms:</u>
-0.8m + 3 - 12.5m + 95.36m
-13.3m + 3 + 95.36m
82.06m + 3
82.06m + 3 is your simplified expression.
I think it would be 117
Because H is 63
So 90+90+63=243
360-243=117
I used 360 because angles in quadrilaterals add up to 360 degrees
The answer is -4 2/3
Explanation : The elevator is at 0, and went below ground level 90 feet, that would be -90, then it went up 20 feet, which would be -90 + 20 = -70
-70 ft / 15sec = - 4 2/3
I am not sure about the ground level and negative difference but that it is what I was taught. Below ground level is negative and above is positive. Therefore the elevator traveled up and it traveled -4 2/3 per second.
It so either 4 2/3 or - 4 2/3 but pretty sure it is - 4 2/3.
:)))
Answer:
the left side of the line
Step-by-step explanation:
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
