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3 years ago

Find the area of the polygon

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

7 0

Answer:

Step-by-step explanation:

The area of a parallelogram is just b*h

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You earn $8.50 per hour at your summer job. Write and solve an inequality that represents the number of hours you need to work i

r-ruslan [8.4K]

Answer:

8.50x $\geq$ 348.50

41 hours

Step-by-step explanation:

x= amount of hours

5 0

3 years ago

A number less than 37 in algebraic expression

kherson [118]

Step-by-step explanation:

A number: A number usually represents a variable. In this case, we will use X.

Less than: Less than means that the sign should be facing to the right because the number on the left is “less than” the one on the right: < < < <

Answer: A number (X) (Less than)< 37:

X < 37

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3 years ago

Find the z-score that has 62.8% of the distribution’s area to its left

ArbitrLikvidat [17]

$\mathbb P(Z$

where $F_Z(z)$ is the cumulative distribution function for the random variable $Z$ following the standard normal distribution.

5 0

3 years ago

Joan wants to reduce the area of her posters by one-third. Draw lines to match the original dimensions in the left column with t

3241004551 [841]

Answer:

1) $30\ in\ by\ 12\ in$ --------> $120\ in^{2}$

2) $30\ in\ by\ 18\ in$ --------> $180\ in^{2}$

3) $12\ in\ by\ 15\ in$ --------> $60\ in^{2}$

4) $18\ in\ by\ 15\ in$ --------> $90\ in^{2}$

Step-by-step explanation:

Verify each case

case 1) $30\ in\ by\ 12\ in$

Find the area with the original dimensions

$A=30(12)=360\ in^{2}$

Reduce the area of the poster by one-third

$360/3=120\ in^{2}$

therefore

$30\ in\ by\ 12\ in$ --------> $120\ in^{2}$

case 2) $30\ in\ by\ 18\ in$

Find the area with the original dimensions

$A=30(18)=540\ in^{2}$

Reduce the area of the poster by one-third

$540/3=180\ in^{2}$

therefore

$30\ in\ by\ 18\ in$ --------> $180\ in^{2}$

case 3) $12\ in\ by\ 15\ in$

Find the area with the original dimensions

$A=12(15)=180\ in^{2}$

Reduce the area of the poster by one-third

$180/3=60\ in^{2}$

therefore

$12\ in\ by\ 15\ in$ --------> $60\ in^{2}$

case 4) $18\ in\ by\ 15\ in$

Find the area with the original dimensions

$A=18(15)=270\ in^{2}$

Reduce the area of the poster by one-third

$270/3=90\ in^{2}$

therefore

$18\ in\ by\ 15\ in$ --------> $90\ in^{2}$

6 0

4 years ago

4 2/3 divided by 1/2

ycow [4]

Answer:

9 1/3

Step-by-step explanation:

1. Make 4 2/3 into a improper fraction

4 2/3= 14/3

2. Keep, change, flip

14/3 x 2/1

3. Multiply

14/3 x 2/1= 28/3

4. Simplify

28/3= 9 1/3

(btw keep, change, flip basically means to keep the first fraction the way it is, change the division sign to a multiplication sign, then flip the second fraction so the original denominator is the new numerator, and vise versa.)

3 0

3 years ago

Read 2 more answers