What is the width (or height) of the parking lot?

What are the total amount of choices possible if an individual is to create a 4 digit password using the digits 0 through 9 incl

qwelly [4]

9000 ways to create 4-digit passwords using digits from 0 to 9 that the first character can't be 0, but not using the digit 0 as the first character.

We have to see how many different 4-digit passwords we can create by using digits from 0 to 9, such that the first character can't be 0.

<h3>What is the combination?</h3>

Each of the different groups or selections can be formed by taking some or all of a number of objects, irrespective of their arrangments is called a combination.

Here we have 4 selections.

Now let's find the number of options for each of these:

First character = 9 options {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Second character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Third character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Fourth character = 10 options {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

The total number of different combinations is just the product of these 4 numbers:

C = 9×10×10×10 = 9,000

So, we can conclude that the correct option is D.

If you want to learn more about combinations visit here;

brainly.com/question/2280026

4 0

2 years ago

Read 2 more answers

Here is a diagram and its corresponding equation. Find the solution to the equation.

Katen [24]

4(x + 7) = 38

Since there is no operation sign between the 4 and parenthesis, it makes it an automatic multiplication problem.

You would use distributive property to multiply each which should leave your equation looking like this afterwards:

4x + 28 = 38
(4 times x and 4 times 7)

You would then solve it like a two step equation,

1. +28 - 28 = 0
2. 38 - 28 = 10

4x = 10

10 divided by 4 = 2.5

x = 2.5

We can recheck our work by substituting in the value of x.

4(2.5 + 7) = 38

10 + 28 = 38

When we substituted in the value, it gave us the correct inequality.

Therefore,
x = 2.5

5 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{

Jlenok [28]

Answer:

$x>2$

Step-by-step explanation:

When given the following inequality;

$(x^2+x-3):(x^2-4)\geq1$

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

$\frac{x^2+x-3}{x^2-4}\geq1$

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

$\frac{x^2+x-3}{x^2-4}-1\geq0$

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

$\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0$

Perform the operation on the other side distribute the negative sign and combine like terms;

$\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0$

Factor the equation so that one can find the intervales where the inequality is true;

$\frac{x+1}{(x-2)(x+2)}\geq0$

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

$-1, 2, -2$

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

$x\leq-2\\-2$

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

$x\leq-2$ -> negative