Answer:
x=20
Step-by-step explanation:
Answer: 0.0548
Step-by-step explanation:
Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.
Let
represents the sample mean GPA for each student.
Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:
![P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28%5Coverline%7BX%7D%3E3.42%29%3DP%28%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%3E%5Cdfrac%7B3.42-3.5%7D%7B%5Cdfrac%7B0.5%7D%7B%5Csqrt%7B100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28Z%3E%5Cdfrac%7B-0.08%7D%7B%5Cdfrac%7B0.5%7D%7B10%7D%7D%29%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%3DP%28Z%3E1.6%29%5C%5C%5C%5C%3D1-P%28Z%3C1.6%29%5C%5C%5C%5C%3D1-0.9452%3D0.0548)
hence, the required probability is 0.0548.
<em>Hey</em><em>!</em><em>!</em><em>!</em>
<em>Here's</em><em> </em><em>your</em><em> </em><em>answer</em><em>:</em>
<h3>
<em><u>Domain</u></em><em><u>:</u></em><em><u>{</u></em><em><u>(</u></em><em>0</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>8</em><em>)</em><em>}</em></h3><h3>
<em>Range</em><em>:</em><em>{</em><em>(</em><em>2</em><em>,</em><em>3</em><em>,</em><em>7</em><em>,</em><em>9</em><em>)</em><em>}</em></h3>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>. </em><em> </em><em> </em><em> </em><em> </em>
<h3>
<em>have</em><em> </em><em>a</em><em> </em><em>great</em><em> </em><em>day</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h3>
Answer:
Solution given:
opposite:9
adjacent: 12

Relationship between opposite and adjacent is given by tan angle
so




#11.
hypotenuse[h]=11cm
opposite/perpendicular[P]=b cm
adjacent/base[b]=a cm
now

Relationship between height and hypotenuse is given by Sin angle
:.
Sin 62°=
doing crisscrossed multiplication
b=Sin 62°*11
:.b=9.71 cm
a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.
again
Relationship between base and hypotenuse is given by Cos angle
:.Cos 62°=
doing crisscrossed multiplication
a=Cos 62°×11
a=5.16cm
b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>
Answer:
It would be 8 1/6 im 90% sure
Step-by-step explanation: