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abruzzese [7]
3 years ago
11

A relay team of 4 swimmers is to be formed from a swim team with 20 member. How many different relay teams are possible?

Mathematics
1 answer:
Mars2501 [29]3 years ago
5 0
<span>When order does not matter you use what is called n choose k formula

n!/(k!(n-k)!) where n is the number of things to choose from and k is the number of choices made, in this case:

20!/(4!(20-4)!)=4845</span>
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−4x+35&gt;2<br> Whats the innequality
geniusboy [140]

-4x + 35 > 2

Subtract 35 from both sides:

-4x> -33

Divide both sides by -4:

X > -33 s -4

Because you are dividing the inequality. Y a negative value, reverse the inequality sign.

X < 33/4

7 0
4 years ago
How will the graph of the function f(x) = 3* translate when the function is changed to f(x) = 3(x-2)?
Lelechka [254]

Answer: B

Step-by-step explanation:

6 0
3 years ago
Someone help me out on these 2 geometry questions, ASAP!!!<br> “Complete the proofs”
vodomira [7]

<u>Question 11</u>

1) \overline{BA} \cong \overline{FA}, \angle 1 \cong \angle 2 (given)

2) \angle A \cong \angle A (reflexive property)

3) \triangle AEB \cong \triangle ACF (ASA)

4) \overline{AC} \cong \overline{AE} (CPCTC)

<u>Question 12</u>

1) Isosceles \triangle ACD with \overline{AC} \cong \overline{AD}, \overline{BC} \cong \overline{ED} (given)

2) \angle ACD \cong \angle ADC (angles opposite congruent sides in a triangle are congruent)

3) \angle ACB and \angle ACD are supplementary. \angle ADC and \angle ADE are supplementary (angles that form a linear pair are supplementary)

4) \angle ACB \cong \angle ADE (supplements of congruent angles are congruent)

5) \triangle ABC \cong \triangle AED (SAS)

6) \overline{AB} \cong \overline{AE} (CPCTC)

7) \triangle ABE is an isosceles triangle (a triangle with two congruent sides is isosceles)

<em>Note: I changed the names of the segments in Question 11 because of the word filter.</em>

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2 years ago
Determine the length of the radius of the circumscribed circle to the right triangle with the legs 7 cm and 4cm.Round your answe
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Answer:

4.03cm

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Note that the diameter of the circumscribed circle to the right triangle is the hypotenuse of the triangle.

To get the diameter, we will use the pythagoras theorem as shown;

d² = 7² + 4²

d² = 49 + 16

d² = 65

d = √65

d = 8.0622577

Since radius = d/2

radius = 8.0622577/2

radius = 4.0311288

Hence the radius of the circumscribed circle to the nearest hundredth is 4.03cm

6 0
3 years ago
Qestion in the photo
nalin [4]

2) -3,3

Explanation : -3+3 =0

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3 years ago
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