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CaHeK987 [17]
3 years ago
12

Help please I don’t know the answer

Mathematics
2 answers:
Tpy6a [65]3 years ago
6 0

Answer:

4 x 10 -2

Step-by-step explanation

the numbers in bold are what you type into the boxes

anastassius [24]3 years ago
4 0
Is it 5•10 power of 2
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Judi solved the equation 1 - 18 = 43. Her work is shown.<br> What error did Judi make?
Anna11 [10]
The anwser is 17 idk what she did but that’s wrong
4 0
3 years ago
Read 2 more answers
Use DESMOS: What is the equation
Masja [62]

y=mx+c

I picked the points (0, -4) and (-2,-10) to find the gradient of the line

M= rise/run

= 6/2

=3

Y-intercept is at - 4

Y= 3x - 4 is equation of the line given

Reciprocal of 3 is 1/3

(m1 x m2 = - 1)

So, to make - 1, our second gradient should be negative.

Gradient of the perpendicular line will be - 1/3

Y= - 1/3x + c

Substitute value of x & y into the equation

(-6,6) means x = - 6, y = 6

y = - 1/3x +c

6 = - 1/3 x - 6 + c

6 = 2 + c

-2

4 = c

Thus, final equation we're after will be:

y= - 1/3x + 4

Hope this helps!

6 0
2 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
What is the decimal equivalent for 139%
laiz [17]

Answer: 1.39

Step-by-step explanation:

Hope it helps! Mark me brainliest.

7 0
3 years ago
1. Isaac goes to an amusement park where tickets for the rides cost $10 per sheet and tickets for the shows cost $15 each.
Degger [83]
The answers I have gotten are
A- x+y= $25
B- $95
7 0
4 years ago
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