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algol [13]
3 years ago
5

Fatima evaluated the expression when m = -2 and n = 4. Her work is shown below.

Mathematics
2 answers:
Irina18 [472]3 years ago
5 0

Answer: -She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2.

Step-by-step explanation:

The work of Fatima is the next one:

She starts with the equation:

\frac{4m^{-3}n^{-2}  }{m^{-1}n^{2}  }

Now, she simplifies:

\frac{4m^{-3}n^{-2}  }{m^{-1}n^{2}  } = 4m^{-3 - (-1)} m^{-2 -1} = 4m^{-2} n^{-3}

Now she replaces the values of n and m:

4(-2)^{-2} (4)^{-3}

And here she makes her error, she transforms the:

4*(-2)^-2 into (-8)^-2

So the exponent that only was affecting the -2, is now affecting the product 4*(-2)

Then the answer is the third option:

"-She applied the exponent -2 to 4(-2) instead of applying the exponent to just -2."

Kruka [31]3 years ago
4 0

Answer:

The answer to your question is: third option is correct.

Step-by-step explanation:

The third option is correct

                                           4(-2)⁻²(4)⁻³

                                           \frac{4}{(2)^{2}(4)^{3}}}

                                           

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Read 2 more answers
1. ) Consider the function f(x)=5−7x2,−5≤x≤1
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1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.

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Absolute minimum value: x = 1
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2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:

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c=- \frac{1}{2}

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