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shepuryov [24]
3 years ago
9

In order to make green paint a 2:3 ratio of blue paint and yellow paint is used.If there are 30 ounces of green paint how many o

unces of blue paint was needed
Mathematics
1 answer:
gladu [14]3 years ago
6 0

Answer:

There are 30 ounce of green paint 18 ounces blue paint was needed.

Step-by-step explanation:

Given that,

In order to make green paint a 2:3 ratio of blue paint and yellow paint is used.

Assume 2x blue paint and 3x yellow paint required to make 30 ounce of green paint.

According to the problem,

2x+3x=30

⇒5x=30

\Rightarrow x=\frac {30}{5}

⇒ x=6

The amount of blue paint is = 2×6

                                              =12 ounces

The amount yellow paint is = (3×6)

                                            = 18 ounces

There are 30 ounce of green paint 18 ounces blue paint was needed.

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Answer:

Step-by-step explanation:

Hello,

<em>"Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only."</em>

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WILL MAKE BRAINLIEST!!! A Ferris wheel has a diameter of 220 feet and the center of the wheel is 125 feet above the ground. The
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Since the radius of a circle is half its diameter, the radius of our Ferris wheel is r= \frac{220}{2} =110ft

Next, we are going to convert from revolutions per minute to degrees per second.
We know that t<span>he wheel makes a complete turn every 2 minutes, so it makes a complete turn in 120 seconds. Since there are 360° in a complete turn, we can set up our conversion factor:
</span>\frac{1*360}{120}=3 degrees per second 
<span>
Now, lets find the height:
</span>We know that <span>the passenger is at the lowest point on the wheel when t=0; since the wheel is 125 feet above the ground, at t=0 h=125. To find t at the top, we are going to take advantage of the fact that the wheel will turn 180° from the lowest point to the top and that it turns 3° every second:
</span>t= \frac{180}{3}
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Notice that the height at the top is the diameter of the wheel plus the height above the ground, so h=220+125=345.

To model the situation we are going to use the cosine function, but notice that cos (\alpha) is 1 when \alpha =0 and -1 wen \alpha =180. Since we want the opposite, we are going to use negative cosine.
Notice that we want \alpha =180 when t=60, so we are going to use -cos(3t). Next, we are going to multiply our cosine by the radius of our wheel: -110cos(3t), and last but not least we are going to add the sum of the radius of the wheel plus the height above the ground:
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Now that we have our height function lets check if everything is working:
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</span>h=225-110cos(3t)
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h=225-110cos(3t)
h=225-110cos(3*60)
h=225-110cos(180)
h=345feet 

We can conclude that cosine function that express the height h (in feet) of a passenger on the wheel as a function of time t (in minutes) ) is: h=225-110cos(3t)
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Step-by-step explanation:

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