<u>Solution for question 1:</u>
Put it in this format:
Solving;
2(²-³) × 10^(15-9)
2^-1 × 10^6 = 1/2 × 10^6
That gives 5 × 10^5
<u>Solution to question 2:</u>
Solving;
2^(1 - 2) × 10^(-5 + 12)
= 1/2 × 10^7
That gives;
5 × 10^6
Jamal's Lawn Service will charge $28 for fertilizing this lawn.
Step-by-step explanation:
- Step 1: Find the area of the lawn. It is in U shape which is a rectangle from which a square has been cut off. So the area of the lawn can be found by subtracting the area of the square from the area of the rectangle.
Area of the rectangle = length × width; here length = 4 yd and width = 3 yd
⇒ Area = 4 × 3 = 12 yd²
Area of the square = (side length)²; Here side length = 2 yd
⇒ Area = 2² = 4 yd²
∴ Area of the lawn = 12 - 4 = 8 yd²
- Step 2: Find the cost of fertilizing the lawn.
Cost of fertilizing 1 sq. yd = $3.50
∴ Cost of fertilizing 8 sq. yards = 8 × 3.50 = $28
Answer:
r = -7
Step-by-step explanation:
Solve for r:
8 r + 9 = -4 (3 - r) - 7
-4 (3 - r) = 4 r - 12:
8 r + 9 = 4 r - 12 - 7
Grouping like terms, 4 r - 12 - 7 = 4 r + (-7 - 12):
8 r + 9 = 4 r + (-7 - 12)
-7 - 12 = -19:
8 r + 9 = 4 r + -19
Subtract 4 r from both sides:
(8 r - 4 r) + 9 = (4 r - 4 r) - 19
8 r - 4 r = 4 r:
4 r + 9 = (4 r - 4 r) - 19
4 r - 4 r = 0:
4 r + 9 = -19
Subtract 9 from both sides:
4 r + (9 - 9) = -9 - 19
9 - 9 = 0:
4 r = -9 - 19
-9 - 19 = -28:
4 r = -28
Divide both sides of 4 r = -28 by 4:
(4 r)/4 = (-28)/4
4/4 = 1:
r = (-28)/4
The gcd of -28 and 4 is 4, so (-28)/4 = (4 (-7))/(4×1) = 4/4×-7 = -7:
Answer: r = -7
Answer:
The answer is -4.
Step-by-step explanation:
Since its f/g, we know that f(n)= 2n^2+2n and g(n)=n+1.
N= -2. You will plug in all the values of n = - 2.
So...
2n^1+2n/n+1
2(-2)^2+2(-2)/-2-1 which will give you -4.
The answer should be ................... 100