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3 years ago

13

Suppose that the amount of algae in a pond doubles every 4 hours. If the pond initially contains 90 pounds of algae, how much al

gae will be in the pond after 12 hours?
-720 pounds
-360 pounds
-1440 pounds
-114 pounds

1 answer:

UNO [17]3 years ago

4 0

After 12 hours the pound would have 720 pounds of algae.

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-9/54 - (-12/54)<br><br> What is the answer in fraction form?

Fofino [41]

Answer:

1/18

Step-by-step explanation:

Just go to calculator and write -9÷54-(-12÷54)

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2 years ago

Two bonds are available on the market as follows:

erastova [34]

Answer:

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

P represents the principal or initial amount invested.

R represents the interest rate.

T represents duration of the investment in years

From the information given,

P = $750

R = 5%

T = y years

I = the total return of Bond 1 - principal

I = 1000 - 750 = $250

Therefore,

250 = (750 × 5 × y)/100

250 = 37.5y

y = 250/37.5

y = 6.7 years

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3 years ago

Read 2 more answers

Static and Reasoning:

Serggg [28]

Based on the data recorded by Isabella, it can be concluded the cube is rather fair.

<h3>How many times did Isabella get each number?</h3>

Based on the data, here are the results:

Getting a 1: 6 times
Getting a 2: 5 times
Getting a 3: 7 times
Getting a 4: 5 times
Getting a 5: 6 times
Getting a 6: 7 times

This implies, in total Isabella got the same number between five and seven times. For example, the number 2 was obtained 5 times, but the number 3 was obtained 7 times.

<h3>What can be concluded based on the results?</h3>

Even though Isabella did not get the same number of times each number, the dice is rather fair because by rolling the dice thirty six times you will obtain the same number at least five times.

Moreover, there is not a big difference in the number of times you obtain each number.

Learn more about dice in: brainly.com/question/23637540

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1 year ago

Verify the property a x (b+c) =(a x b)+(a x c) by taking: a = -7, b = (2/5), c = (-3/7)

Margaret [11]

(-7)*(2/5 + (-3/7))
= -14/5 + 3
=1/5

5 0

3 years ago

A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimet

Dima020 [189]

Let's find the perimeter of the window.

The bottom side is $x$ . The left and right sides make $2y$ .
The perimeter of a circle is $2\pi r$ , so the perimeter of a semicircle must be $\pi r$ , The radius is $\frac{1}2x$ , so that gives $\frac{1}2\pi x$ for the curve. All of that is equal to 12.

$x+2y+\frac{1}2\pi x=12$

We only want to use one variable to create the area formula, so let's solve for $y$ .

$2y=12-x-\frac{1}2\pi x$

$y=6-\frac{1}2x-\frac{1}4\pi x$

Now that we have a value for $y$ in terms of $x$ , we can find the area in terms of $x$ .

The area of the rectangle is going to be $xy$ , which then becomes

$A_r=x(6-\frac{1}2x-\frac{1}4\pi x$

$A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2$

The area of the semicircle is going to be $\frac{1}2\pi r^2$ .

Since $r=\frac{1}2x$ , $A_{sc}=\frac{1}2\pi (\frac{1}2x)^2$ .

$A_{sc}=\frac{1}2\pi \frac{1}4x^2$

$A_{sc}=\frac{1}8\pi x^2$

Now let's add the areas of the rectangle and semicircle.

$A=A_r+A_{sc}$

$A=6x-\frac{1}2x^2-\frac{1}4\pi x^2+\frac{1}8\pi x^2$

$A=6x-\frac{1}2x^2-\frac{1}8\pi x^2$

If you wanted to factor out $\frac{1}8$ like you did, this would become

$\boxed{A(x)=\frac{1}8(48x=4x^2-\pi x^2)}$

Now what we want to do is find what $x$ is when $A$ is at its highest point, Once we have the value for $x$ we can also find the value for $y$ , of course.

Let's put our equation in the general form of a quadratic.

$A(x)=(-\frac{1}2-\frac{1}8\pi )x^2+6x$

Now we can use the vertex formula $x=\frac{-b}{2a}$ .
( $a$ and $b$ refer to $ax^2+bx+c$ .)

$x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}$

$x=\frac{-6}{-\frac{1}4\pi -1}$

$x=\frac{-24}{-\pi -4}$

$\boxed{x=\frac{24}{\pi +4}}$

Now let's plug that in for $y=6-\frac{1}2x-\frac{1}4\pi x$ .

Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use $x\approx3.36059492$ .

$y\approx6-\frac{1}2(3.36059492)-\frac{1}4\pi(3.36059492)$

<span> $y\approx6-(1.68029746+2.63940507809)$

</span><span> $\boxed{y\approx1.68029746191}$

Let's take our answers for $x$ and $y$ and round to 2 decimal places.

$\boxed{x\approx 3.36\ ft}$

$\boxed{y\approx 1.68\ ft}$ </span>

3 0

3 years ago