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zubka84 [21]
3 years ago
15

Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum

of two times the number of test tubes and five times the number of beakers is 450, If b is the number of beakers and t is the number of test tubes, the system of linear equations representing this situation is ...
The number of beakers in the school’s lab is ... and the number of test tubes in the school’s lab is...
Mathematics
2 answers:
Gnoma [55]3 years ago
8 0
Answer
Beakers: 30
Test tubes: 150
frutty [35]3 years ago
5 0

Answer:

The numbers of test tubes are 150 and beakers are 30.

Step-by-step explanation:

we have to  find numbers of beaker ans test tubes in chemistry lab

Given statement is "Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum of two times the number of test tubes and five times the number of beakers is 450"

Let the number of beakers be b

and Let the number of test tubes be t

According to question

5t-3b=660           ......(1)

2t+5b=450          ......(2)

solve linear equation by substitution method,

isolate the b in equation (1)

5t-3b=660

subtract both the sides by 5t,

-3b=660-5t

divide both the sides  by -3,

tex]b=\frac{5t-660}{3}[/tex]

substitute the value of b in equation (2)

2t+5(\frac{5t-660}{3})=450

2t+(\frac{25t-3300}{3})=450

multiply both the sides by 3,

6t+25t-3300=1350

31t-3300=1350

Add  both the sides by 3300,

31t=1350+3300

31t=4650

divide both the sides by 31,

t=150

the numbers of test tubes are 150.

Put the value of t in equation (1)

5t-3b=660

5(150)-3b=660

750-3b=660

subtract both the sides by 750,

-3b=660-750

-3b=-90

divide both the sides by -3,

b=30

the numbers of beakers are 30.

Therefore, the numbers of test tubes are 150 and beakers are 30.

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