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3 years ago

Question vvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

Mathematics

2 answers:

mamaluj [8]3 years ago

7 0

X=28 and x=0 hope this helps

gavmur [86]3 years ago

3 0

Answer:

x = 28 and x = 0

Step-by-step explanation:

Find all solutions for x by breaking the absolute value into the positive and negative components.

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She drew a right triangle

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Write 27/22 as a decimal rounded to the nearest tenth?

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Sergeu [11.5K]

Answer:

5 pints per hour.

Step-by-step explanation:

Morning:

Given:

Number of strawberries packed in every 4 minutes = 3

∴ Number of strawberries packed in every one minute = $\frac{3}{4}$

So, number of strawberries packed in every 60 minutes = $\frac{3}{4}\times 60=45$

1 hour = 60 minutes.

So, strawberries are packed at a rate of 45 pints per hour in the morning.

Afternoon:

Number of strawberries packed in every 3 minutes = 2

∴ Number of strawberries packed in every one minute = $\frac{2}{3}$

So, number of strawberries packed in every 60 minutes = $\frac{2}{3}\times 60=40$

1 hour = 60 minutes.

So, strawberries are packed at a rate of 40 pints per hour in the afternoon.

Difference between the packing rates is given as:

Morning rate - Afternoon rate = 45 - 40 = 5 pints per hour.

So, she packed 5 more pints in one hour in the morning than in the afternoon.

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3 years ago

The length, l, that a spring is stretched varies directly as the amount of force, F, applied to the end of the spring. When a fo

Elina [12.6K]

Answer:

C. 4.5 inches

Step-by-step explanation:

Given the following data;

Force, F = 10 pounds

Extension, e = 3 inches

First of all, we would determine the spring constant (k) using the following formula;

Force = spring constant * extension

10 = spring constant * 3

Spring constant = 10/3

Spring constant = 3.33 pounds per inches.

Next, we would find the extension of the spring when a force of 15 pounds is applied;

F = ke

15 = 3.33 * e

Extension, e = 15/3.33

Extension, e = 4.5 inches.

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3 years ago