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il63 [147K]
3 years ago
8

Which ordered pair is a solution of the equation?

Mathematics
2 answers:
Maru [420]3 years ago
6 0
A only 3= 5(2-2)+3
3= 5(0)+3
choli [55]3 years ago
4 0
The answer is A. Hope this helps!
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What is the 22nd term of the arithmetic sequence 12, 17, 22, 27, …?
melomori [17]
In simple words you just find what is being added to each term in order to get the next term. Subtracting 17 by 12 you get 5, 22 minus 17 is 5 as well. Now that what is being added is found, you go by the last term given which is 27. You keep adding 5 to the number until you get to the 22nd term which would result in 117. If you would want to know the equation in order for it to be plugged in then you would use f(x)= 7+5x . You would want to use this equation instead of f(x)= 12+5x because putting 1 as x would make it equal to 17 which is NOT the first term but the second.
4 0
3 years ago
Read 2 more answers
Pls give me the answer! Thanks!
Mademuasel [1]

Answer:

6

Step-by-step explanation:

7 x 6 = 42 + 9 = 51 + 54 = 105 + 75= 180

6 0
2 years ago
Read 2 more answers
Suppose that you are offered the following "deal.
MissTica

Answer:

expected profit is  - $0.50

Step-by-step explanation:

1  $(7.00) 0.166666667  $(1.17)

2  $(7.00) 0.166666667  $(1.17)

3  $1.00  0.166666667  $0.17  

4  $1.00  0.166666667  $0.17  

5  $1.00  0.166666667  $0.17  

6  $8.00  0.166666667  $1.33  

   

   $(0.50)

3 0
2 years ago
Y = |x-4|+6 The axis of symmetry is x=
Troyanec [42]

Answer:

Y = |x-4|+6 The axis of symmetry is x=xxx se_x.com

Step-by-step explanation:

8 0
3 years ago
If 16 is added to one-third of a number, the result is three times the number. What is the number?
AnnZ [28]
First set up the equation based on the description.

\frac{1}{3} x + 16 = 3x

Use subtraction to get the "x"s on one side of the equation. You can next subtract <span>\frac{1}{3} x from both sides.

16 = </span>\frac{8}{3}<span> x

Now you can multiply both sides of the equation by </span>\frac{3}{8}<span>  to solve for x

x = 6</span>
4 0
3 years ago
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