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3 years ago

Which ordered pair is a solution of the equation?

Mathematics

2 answers:

Maru [420]3 years ago

6 0

A only 3= 5(2-2)+3
3= 5(0)+3

choli [55]3 years ago

4 0

The answer is A. Hope this helps!

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Practice 7) fill in the blanks.

DiKsa [7]

(h,k) is the vertex

b/2a is the line of symmetry

a > 0 parabola opens upward, vertex is a minimum

a < 0 parabola opens downward, vertex is a maximum

My first answer was deleted lolol

7 0

2 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

2 years ago

Annie received a 10% raise last year. If her salary now is $60,000, what was her salary last year?

sergeinik [125]

$6,000 was her salary last year:))

4 0

2 years ago

Fourteen less children’s meals were served than adult meals at a barbecue. Children plate were 1.50 each and adult plates were 2

Annette [7]

Answer:

134 children and 120 adult plates were served

Step-by-step explanation:

let the children mean be x

Let the adult meal be y

If fourteen less children’s meals were served than adult meals at a barbecue, then;

y = x - 14 .... 1

IF Children plate were 1.50 each and adult plates were 2.00 each with a total of 441 in amount then;

1.5x + 2y = 441 .... 2

Substitute 1 into 2;

1.5x + 2(x-14) = 441

1.5x+2x-28 = 441

3.5x = 441+28

3.5x = 469

x = 469/3.5

x = 134

Recall that y = x - 14

y = 134-14

y = 120

Hence 134 children and 120 adult plates were served

7 0

2 years ago

HELPPP....PLEASE...........

kogti [31]

Answer:

9 1/3, 12 1/2, 14 3/4

Step-by-step explanation:

I assume the formula you’re working with is A=b*h since nothing says otherwise...

((Patio 1))

So you have your area (147) and your base (15 3/4), now you need to plug them in, which should look like this:

147= 15 3/4*h

You need to isolate your h in order to get the missing number, so you should divide both sides by 15 3/4 OR 63/4 ((15*3—>60+3=63))

Dividing by a fraction is the equivalent of multiplying by its reciprocal... so

147 * 4/63 = 588/63 which can be simplified to 84/9 once both the numerator and denominator are divided by 7

In mixed number for it is 9 3/9 which simplified becomes 9 1/3

You solve the other similarly

3 0

3 years ago