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3 years ago

Which ordered pair is a solution of the equation?

Mathematics

2 answers:

Maru [420]3 years ago

6 0

A only 3= 5(2-2)+3
3= 5(0)+3

choli [55]3 years ago

4 0

The answer is A. Hope this helps!

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A woman make n basket and sell the all at the same price

Charra [1.4K]

Yay you’re not getting a profit because of how revenue works but I mean You made a basket

7 0

3 years ago

Is the quotient of 3/5 ÷ 6/7 greater than or less than 3/5? Explain

Vikki [24]

The quotient of two fraction is the multiplication between the first and the inverse of the second:

$\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \cdot \dfrac{d}{c}$

So, in your case, you have

$\dfrac{3}{5} \div \dfrac{6}{7} = \dfrac{3}{5} \cdot \dfrac{7}{6} = \dfrac{7}{10}$

So, the question now is: which is larger, 7/10 or 3/5? To answer this question, transform the second fraction so that it will have denominator 10 as well:

$\dfrac{3}{5} = \dfrac{3\cdot 2}{5 \cdot 2} = \dfrac{6}{10}$

So, now it is clear that

$\dfrac{7}{10} > \dfrac{6}{10}$

3 0

3 years ago

Read 2 more answers

Consider the equation Y=-2x+5 Create a table of five ordered pairs that satisfy the equation. What is the slope of the line repr

Vikentia [17]

Five pairs of points (X,Y) that satisfy the equation Y=-2X+5 may be the following:

For X=0: Y=-2*0+5=5 (0,5)

For X=1: Y=-2*1+5=3 (1,3)

For X=2: Y=-2*2+5=1 (2,1)

For X=3: Y=-2*3+5=-1 (3,-1)

For X=4: Y=-2*4+5=-3 (4,-3)

The slope of the function is m=-2. Correct answer: C

5 0

3 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago

PLEASE PLEASE HELP ME

mina [271]

The answer is <EKF and <HKI

3 0

3 years ago