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Romashka [77]
4 years ago
7

Pls help I can’t do this 20 points

Mathematics
1 answer:
Serhud [2]4 years ago
8 0

Answer:

u have it done now right?

Step-by-step explanation:

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Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
4 years ago
Heme d hey the girl who helped me please hl
mestny [16]

Answer:

Parallel segments → 1

perpendicular segments → 2

congruent segments → 3

---------

hope it helps...

have a great day!!

5 0
3 years ago
Read 2 more answers
How do you find the percent error?
natita [175]
(Observed data - Accepted standard) divided by the accepted standard. Then all of that is multiplied by 100.

( ( O - A ) / A) * 100
6 0
3 years ago
1/2 (4 - 2x); 2-2x can some one help​
lakkis [162]

Answer:

x=0

Step-by-step explanation:

7 0
3 years ago
laws of Sines with find the angle. Find each measurement indicated. Round your answers to the nearest tenth. Show your work plea
Gwar [14]

Answer:

4. Z ≈ 46.1°

5. T ≈ 45.2°

6. F ≈ 15.0°

Step-by-step explanation:

4.

We need to use the Law of Sines, which states that for a triangle with legnths a, b, and c and angles A, B, and C:

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Here, we can say that ZY = a = 30, X = A = 110, XY = b = 23, and Z = B. Plug these in to find Z:

\frac{a}{sinA} =\frac{b}{sinB}

\frac{30}{sin(110)} =\frac{23}{sinZ}

Solve for Z:

Z ≈ 46.1°

5.

Use the Law of Sines as above.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{26}{sin(76)} =\frac{19}{sinT}

Solve for T:

T ≈ 45.2°

6.

Again, use the Law of Sines as before.

\frac{a}{sinA} =\frac{b}{sinB}

\frac{29}{sin(137)} =\frac{11}{sinF}

Solve for F:

F ≈ 15.0°

6 0
3 years ago
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