The positions of the sun, earth and shooting star form a right angled triangle, where distance between earth and sun is 'y', and the angle 'x°' is given
Now, in a right angled triangle using trigonometry, we can determine a side of the triangle is one of the sides and one of the angles is known
Here, if we use cos x =  we can determine the distance between the shooting star and the sun. This can be done because we know that the base is 'y', the angle is x° and the hypotenuse represents the distance between the sun and the shooting star
 we can determine the distance between the shooting star and the sun. This can be done because we know that the base is 'y', the angle is x° and the hypotenuse represents the distance between the sun and the shooting star
Note: cos values for each x are definite.
 
        
             
        
        
        
The first one might be b or c
        
             
        
        
        
Answer:
∠A = 84°
Step-by-step explanation:
Since AB and AC are tangent to the circle, ∠ABK = 90° and ∠ACK = 90°.
Angles of a quadrilateral add up to 360°, so:
∠A + 90° + 90° + 96° = 360°
∠A = 84°
 
        
             
        
        
        

The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x) 
It is where cos(4x-π) = 0 
cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2 
4x - π = π/2 
4x = π/2 + π 
4x = 3π/2 
x = 3π/8 
4x - π = 3π/2 
4x = 3π/2 + π
4x = 5π/2 
x = 5π/8 
This ones outside the interval (5π/8 > π/2) , try -π/2 
4x - π = -π/2 
4x = -π/2 + π 
4x = π/2 
x = π/8 
Asymptotes are π/8 and 3π/8 
 
        
             
        
        
        
Answer:
a+3
Step-by-step explanation:
You cannot go any further in answering this question.  These two terms are not like terms so they cannot be combined.  Therefore, the answer is just a+3 itself.