Solve the above question by factoring and applying the Zero-Product property.

Cindy has 2 boxes of pencils. Patrice has 5 boxes of pencils. Each box has the same number of pencils in it.

Murljashka [212]

Answer:

hey mate..

plzz add more to ur question soo that we can answer it...!

;)

8 0

3 years ago

|v|>3 solution to the inequality on the number line

Andrew [12]

On a number line, v would be all the numbers to the left of -3 (for example, |-4|=4 which is greater than 3) and all the values to the right of positive 3. Since it can't equal 3, v=-3 and v=3 are not included on the number line.

3 0

3 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

The area of a triangle is 60 cm2. Its base measures 5 cm. What is the triangle's

dangina [55]

Answer:

24

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I REALLY NEED HELP A$AP

Aleksandr [31]

Answer:

The new length of the garden is 80 ft, the new width is 40 ft, and the total area of the new garden is 3200 ft². The area of the new garden will be 8 times larger than the current one. Jane should make her garden 4 times the current length.

Step-by-step explanation:

Juan's garden is 40 ft in length, he wishes to make the length 2 times longer:

$2 \times 40 = 80$