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kolbaska11 [484]
2 years ago
13

Plz help I need it!!!!!!!!!!!!

Mathematics
1 answer:
AlekseyPX2 years ago
8 0

Answer:

114°

Step-by-step explanation:

? =  \frac{1}{2} (53 \degree + 175 \degree) \\  \\ ? =  \frac{1}{2} \times 228 \degree\\  \\ ? =  114 \degree

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What is the inverse of the function f(x) = 2x + 1?|
padilas [110]

Answer:

1st option

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

\frac{y-1}{2} = x

Change y back into terms of x with x being the inverse h(x)

h(x) = \frac{x-1}{2} = \frac{1}{2} x - \frac{1}{2}

6 0
2 years ago
PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .
Alex

Answer:

21

Step-by-step explanation:

;)

7 0
2 years ago
What is the length of x? What is the length of EF? Only enter numbers in the answer boxes below:
dimaraw [331]

Focus on triangles DFC and DFE:

  • They are both right triangles because DF is perpendicular to EC
  • DC=DE
  • DF is a common side

So, the two triangles are congruent. It follows that CF=FE, and in particular

8x=3x+15 \iff 5x=15 \iff x=3

And since x=3, the length of EF is

EF=3x+15=3\cdot 3+15=24

7 0
3 years ago
ABCD is a square of side 3, and E and F are the mid points of sides AB and BC respectively. What is the area of the quadrilatera
Dima020 [189]
Given : - Square ABCD with side 3.  E and F as midpoints.
To find : - area of EBFD

Solution : - We have, area of square ABCD = 3 x 3 = 9 units.

Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF

arDAE = 1/2 x base x height

=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25

arDFC = 1/2 x base x height 
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25

Thus, (ar) EBFD = arABCD - arDAE - arDCF

= 9 - 2.25 - 2.25

= 4.5 units.

Thus, area of quad EBFD is 4.5 units.  
7 0
3 years ago
How do u do this.I need major help on it
Tpy6a [65]
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

\sf m=\dfrac{y_2-y_1}{x_2-x_1}

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

\sf m=\dfrac{2400-1200}{2-1}

Subtract:

\sf m=\dfrac{1200}{1}

Divide:

\sf m=1200

This is the slope, so we can write the equation:

\boxed{\sf y=1200t}
4 0
3 years ago
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