SOLUTION:
Step 1 :
In this question, we are told that a marketing research company needs to estimate the average total compensation of CEOs in the service industry.
We also have that: Data were randomly collected from 38 CEOs and the 98% confidence interval was calculated to be ($2,181,260, $5,836,180).
Then, we are asked to find the margin error for the confidence interval.
Step 2:
We need to recall that:
![\text{Higher Confidence Interval, CI}_{H\text{ = }}X\text{ + }\frac{Z\sigma}{\sqrt[]{n}}](https://tex.z-dn.net/?f=%5Ctext%7BHigher%20Confidence%20Interval%2C%20CI%7D_%7BH%5Ctext%7B%20%3D%20%7D%7DX%5Ctext%7B%20%2B%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D)
![\text{Lower Confidence Interval , CI}_{L\text{ }}=\text{ X - }\frac{Z\sigma}{\sqrt[]{n}}](https://tex.z-dn.net/?f=%5Ctext%7BLower%20Confidence%20Interval%20%2C%20CI%7D_%7BL%5Ctext%7B%20%7D%7D%3D%5Ctext%7B%20X%20-%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D)
It means that:

![\text{Margin of error, }\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{CI_{H\text{ - }}CI_L}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMargin%20of%20error%2C%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7BCI_%7BH%5Ctext%7B%20-%20%7D%7DCI_L%7D%7B2%7D)
where,


putting the values into the equation for the margin of error, we have that:
![\text{Margin of error,}\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{5,836,180\text{ - }2,181,260\text{ }}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMargin%20of%20error%2C%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7B5%2C836%2C180%5Ctext%7B%20%20-%20%7D2%2C181%2C260%5Ctext%7B%20%7D%7D%7B2%7D)

CONCLUSION:
The margin error for the confidence interval is 1, 827, 460
Answer:
1.-t₁ = 0,625 s
2.-h(max) = 6,25 f
3.-t = 1,25 s
Step-by-step explanation:
V₀ = 20 f/s
h(t) = - 16*t² + 20*t
h(max) = ??
h´(t) = - 32*t + 20
h(max) will occurs when V = 0 dh/dt = 0 then
- 32*t + 20 = 0
- 32*t = -20
t = 20/32
t₁ = 0,625 s
h(max) = h(0,625) = - 16*(0,625)² + 20*0,625
h(max) = - 6,25 + 12,5
h(max) = 6,25 f
c) The ball will hit the ground
t = 2*t₁
t = 2*0,625
t = 1,25 s
Step-by-step explanation:
look at the pic................... hope it helps
The answer to your question is precisely 99
Answer:
12
Step-by-step explanation:
negative times a negative equals a positive.
so, 6 times 2 is 12.