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IRINA_888 [86]
3 years ago
14

Inquashia took out a 2900 loan for a car the interest on the loan is a 8% compounded monthly how much in total will in Isha and

up pain after 6 years. Plz I will Cashapp u some money if u get me right
Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer: the total amount after 6 years is 4690

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount of the loan at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount loaned.

From the information given,

P = 2900

r = 8% = 8/100 = 0.08

n = 12 because it was compounded 12 times in a year.

t = 6 years

Therefore,

A = 2900(1 + 0.08/12)^12 × 6

A = 2900(1 + 0.0067)^72

A = 2900(1.0067)^72

A = 4690

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Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.
RoseWind [281]

Answer:

a. The equation of the parallel line to the given line is y = -4x + 19

b. The equation of the perpendicular line to the given line is y =  \frac{1}{4} x + 2

Step-by-step explanation:

Parallel lines have the same slopes

  • If the slope of one of them is m, then the slope of the other is m

The product of the slopes of the perpendicular lines is -1

  • If the slope of one of them is m, then the slope of the other is -\frac{1}{m}
  • To find the slope of a perpendicular line to a given line reciprocal the slope of the given line and change its sign

The rule of the slope is m = \frac{y2-y1}{x2-x1} , where

  • (x1, y1) and (x2, y2) are the points on the line

The form of the equation of a line is y = m x + b, where

  • m is the slope
  • b is the y-intercept

Let us solve the question

∵ The given line passes through points (1, 6) and (2, 2)

∴ x1 = 1 and y1 = 6

∴ x2 = 2 and y2 = 2

→ Substitute them in the rule of the slope to find it

∵ m = \frac{2-6}{2-1}=\frac{-4}{1}=-4

∴ The slope of the given line is -4

a.

∵ The line is parallel to the given line

∴ Their slopes are equal

∵ The slope of the given line = -4

∴ The slope of the parallel line = -4

→ Substitute its value in the form of the equation above

∴ y = -4x + b

→ To find b substitute x and y in the equation by the coordinates

   of any point on the line

∵ The parallel line passes through the point (4, 3)

∴ x = 4 and y = 3

∵ 3 = -4(4) + b

∴ 3 = -16 + b

→ Add 16 to both sides

∴ 3 + 16 = -16 + 16 + b

∴ 19 = b

→ Substitute it in the equation

∴ y = -4x + 19

The equation of the parallel line to the given line is y = -4x + 19

b.

∵ The line is perpendicular to the given line

∴ The product of their slopes is -1

→ Reciprocal the slope of the given line and change its sign

∵ The slope of the given line = -4

∴ The slope of the perpendicular line = \frac{1}{4}

→ Substitute its value in the form of the equation above

∴ y = \frac{1}{4} x + b

→ To find b substitute x and y in the equation by the coordinates

   of any point on the line

∵ The perpendicular line passes through the point (4, 3)

∴ x = 4 and y = 3

∵ 3 = \frac{1}{4} (4) + b

∴ 3 = 1 + b

→ Subtract 1 from both sides

∴ 3 - 1 = 1 - 1 + b

∴ 2 = b

→ Substitute it in the equation

∴ y =  \frac{1}{4} x + 2

The equation of the perpendicular line to the given line is y =  \frac{1}{4} x + 2

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