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oee [108]
4 years ago
15

A hypothetical element has two main isotopes. One has a mass of 54 amu and the other has a mass of 56 amu. If the atomic weight

of this element is 54.37 amu, what is the percent abundance of the 56 amu isotope?
A) 1. 78.52%
B) 2. 81.52%
C) 3. 75.52%
D) 4. 18.48%
E) 5. 21.48%
Chemistry
1 answer:
castortr0y [4]4 years ago
8 0

Answer:

The answer to your question is: letter D

Explanation:

Data

Isotope mass 1 = 54 amu

Isotope mass 2 = 56 amu

Atomic weight = 54.37 amu

Percent abundance of isotope 2 = ? = X

Percent abundance of isotope 1 = 1 - x

Formula

Atomic weight = (Mass isotope 1)(1 - x) + (mass isotope 2)(x)

Process

Place the data in the formula and solve for x.

54.37 = 54( 1 - x) + 56x

54.37 = 54 - 54x + 56x

54.37 - 54 = -54x + 56x

0.37 = 2x

x = 0.37 / 2

x = 0.185

To find the percent multiply by 100

x = 0.185 x 100

x = 18.5 % = Mass of isotope 2

Mass of isotope 1 = 100 - 18.5 = 81.5 %

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Answer:

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Explanation:

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where g is acceleration due to gravity = 32.17 ft/sec^2

                                     = 196.211\times 32.17 = 6312.12 lbm

b) waist to height ratio = 0.5

waist\ to\  height\  ratio = \frac{circumference\ of\ the\ waist}{height\ of\ the\ person}

circumference of waist =height\  of\  person \times waist\ to\ height ratio

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                                        =37.21 inch

we know that circumference is given as = 2\pi r\ or\  \pi D= 37.21

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3 years ago
What is the oxidation state of an individual phosphorus atom in P O 3 3−?
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Calculate the number of O atoms in 0.364 g of CaSO4 · 2H2O
Nikolay [14]

Answer:

<em>= 7.66 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

Explanation:

For problems like this posting, one needs an understanding of the following topics:

The definition of the mole

<u>1 mole of substance</u> = mass in grams of substance containing 1 Avogadro's Number ( = 6.023 x 10²³ ) of particles of the specified substance. This is generally one formula weight of the substance of interest. From this, the following equivalent relationships should be memorized:

<em>   1 mole = 1 formula weight = 1 mole weight (g)= 6.023 x 10²³ particles</em>

Converting grams to moles:

<em>Given grams => moles = grams/gram formula wt </em>

Converting moles to grams:

<em>Given moles => grams = moles x gram formula wt</em>

_________________________________________________________

<em>Calculate the number of O atoms in 0.364 g of CaSO₄ · 2H₂O.</em>

Given mass CaSO₄ · 2H₂O = 0.364 grams

Formula Wt CaSO₄ · 2H₂O = 172 g/mole

moles CaSO₄ · 2H₂O = mass <em>CaSO4 · 2H2O / formula Wt. CaSO₄ · 2H₂O</em>

<em>= 0.364 g CaSO₄·2H₂O </em><em>/ </em><em>172 g CaSO4·2H2O </em>

<em>= (0.364/172) mole CaSO₄·2H₂O </em>

<em>= 2.12 x 10⁻³ mole CaSO₄·2H₂O    </em>

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<em>= 1.276876 x 10²¹ molecules CaSO₄· 2H₂O   x   6 oxygen atoms / molecule</em>

<em>= 7.661256 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

<em>= 7.66 x 10²¹  oxygen atoms in 0.364 grams of  CaSO₄·2H₂O</em>

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6 0
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Alex Ar [27]

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