Given :
Length , l = 59.8 m.
Breadth , b = 26.6 m.
Depth , d = 3.7 ft .
Density of water , 
.
To Find :
Mass of water in pool .
Solution :
First we will covert depth into m from ft .
For ,
So , volume of pool is :
We know , density is given by :
So , 
Putting given values in above equation :
Hence , this is the required solution.
Answer:
c
Explanation:
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Answer:
0.01134kg
Explanation:
You divide by 1000 to get the kg
Answer:
Theoretical yield for CO₂ is 5.10g
Explanation:
Reaction: 2C₆H₆(l) + 15O₂(g) → 12CO₂(g) + 6H₂O(g)
We convert the mass of oxygen to moles:
4.64 g /32 g/mol = 0.145 moles of O₂
Let's find out the 100% yield reaction of CO₂ (theoretical yield)
Ratio is 15:12. So let's make this rule of three:
15 moles of O₂ can produce 12 moles of CO₂
Therefore 0.145 moles of oxygen will produce (0.145 . 12) /15 = 0.116 moles
We convert the moles to mass: 0.116 mol . 44 g / 1mol = 5.10 g
Density = Mass / Volume
Mass = Density * Volume
Mass = 45 * 7 * 8 * 10
Mass = 25,200 grams
