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PIT_PIT [208]
2 years ago
12

What solutions do we need to work on to get accurate results? A) concentrated B) diluted

Chemistry
1 answer:
Bess [88]2 years ago
7 0
Answer:

A

I hope this helps you!!!
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PLEASE HELP ME ASAP!! I WILL MARK BRAINLIEST!!!
neonofarm [45]

Answer:

D

Explanation:

I did this assignment.

3 0
3 years ago
Read 2 more answers
A covalent bond is best described as ______(A) a bond between two polyatomic ions.(B) a bond between a metal and a nonmetal.(C)
nekit [7.7K]

Answer:

Option C. the sharing of electrons between atoms

Explanation:

Covalent bond is a type of bond in which the reacting element share their valence electrons in order to attain the noble gas configuration.

4 0
3 years ago
What happens along a transform plate boundary?
MAXImum [283]

Answer:

volcanos is the correct answer

7 0
2 years ago
What volume would a sample of gas occupy in LITERS at 0.985 atmospheres and a volume of 3.65 liters if the pressure were raised
musickatia [10]

Answer:

3.18 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 0.985 atm
  • Initial volume (V₁): 3.65 L
  • Final pressure (P₂): 861.0 mmHg
  • Final volume (V₂): ?

Step 2: Convert P₁ to mmHg

We will use the conversion factor 1 atm = 760 mmHg.

0.985 atm × 760 mmHg/1 atm = 749 mmHg

Step 3: Calculate the final volume of the gas

Assuming ideal behavior and constant temperature, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 749 mmHg × 3.65 L/861.0 mmHg = 3.18 L

7 0
2 years ago
A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm
Vsevolod [243]

 The  total pressure  = 1.402 atm


<u><em>calculation</em></u>

Total  pressure = partial  pressure  of gas A + partial pressure of gas B +  partial pressure  of third gas

partial  pressure  of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm


partial pressure for third gas is calculated using ideal  gas equation

that is PV=nRT   where,

p(pressure)=? atm

V(volume) = 8.65 L

n(moles)= 0.200 moles

R(gas constant)=0.0821 L.atm/mol.k

T(temperature) = 11°c into kelvin =11+273 =284 k

make  p the subject of the formula by  diving both side by V

p =nRT/v


p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm



Total  pressure  is therefore = 0.205 atm +0.658 atm +0.539 atm

=1.402 atm

6 0
3 years ago
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