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eimsori [14]
3 years ago
10

Patrick is constructing the circumscribed circle for △RST. Which construction could be his first step?

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

1. Construct the perpendicular bisector of any side of the given triangle. Let it be RS.

Step-by-step explanation:

In order to construct the circumscribed circle for △RST, follow the following steps:

1. Construct the perpendicular bisector of any side of the given triangle. Let it be RS.

2. Construct the perpendicular bisector of another side of the given triangle.Let it be ST.

3. The center of the Circumscribed circle is the point at which they both cross each other.

4. We can draw Circumscribed circle by placing compass on the center point, adjusting its length to reach any corner of the triangle.

Gnom [1K]3 years ago
7 0
Construct the perpendicular bisector of ST
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HELP ASAP!
sladkih [1.3K]

Hey there!!

Let's take the first number as ' x '

Then, the second number would be ' x + 1 '

Sum of these = 183

Hence,

x + x + 1 = 183

2x + 1 = 183

2x = 182

x = \frac{182}{2}

x = 91

Hence, the small integer is 91

Hope my answer helps!

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3 years ago
If f(x) = 3x2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?
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blondinia [14]

Answer:

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Look at attachment

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a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per
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Complete question :

a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per second. how fast is the top of the ladder sliding down the wall at the instant when the base is 4 meters from the wall?

Answer:

-4/3 m/s

Step-by-step explanation:

Using Pythagoras :

a² = x² + c²

5² = x² + y² - - - (1)

The horizontal distance x with respect to time t = 1m/sec

dx/dt = 1m/sec

To obtain the vertical height 'y' with respect to time t when x = 4

5² = x² + y²

Wen x = 4

5² = 4² + y²

25 = 16 + y²

y =√(25 - 16)

y = 3

Differentiate (1) with respect to t

x² + y² = 25 - ---- - (1)

2x * dx /dt + 2y dy/dt = 0

dx/dt = 1

x = 4.

y = 3

2(4)(1) + 2(3) * dy/dt = 0

8 + 6dy/dt = 0

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dy/dt = - 8/6

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8 0
3 years ago
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