First things first, write out your equation without the substitution.
2x+ 2y= 10
Now, put in the substitution.
2x+ 2• 2= 10
Combine like terms.
2x+ 4= 10
Now that your equation it simplified, you need to reverse the problem and put everything on the other side.
2x+ 4= 10
- 4 - 4
2x = 6
2x=6
— —
2 2
X= 3
So the final answer is x=3
You have to start by using the distributive property. So you take the number next to the parentheses which is “8” and you multiply it with “2x”. This gives you “16x”. Then you multiply “8” with “3” and that gives you “24”. You now have the equation “16x + 24 = 48”.
The next step is to subtract “24” with “48”. This leaves you with “24”. Then you now have “16x = 24” as your new equation. The last step is to divide “16x” with “16”, this cancels it out with itself. Then you divide “24” with “16” and you get 1.5. So “X” equals 1.5 or you can convert it into a fraction witch gives you “3/4”.
keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.
Answer:
A. at least two congruent sides
Step-by-step explanation:
Since, we know that,
'An isosceles triangle is a triangle having two sides of equal length or at least two sides of equal length (special case is equilateral triangle)'.
Thus, from the options, we see that,
Options B, C and D are not correct.
<em>Since, congruent sides means that the lengths of the sides are equal.</em>
Thus, we get that,
'An isosceles triangle has at least two congruent sides'.
Hence, option A is correct.
Answer:
Step-by-step explanation:
If it is a parallelogram the opposite sides will a have the same slope.
Using the diagram we see from the coordinates of A and B:
Slope of AB = (5 - -1)/(-1 - -5)
= 6/4
= 3/2.
In the same way
slope of CD = (2 - -4) / (1 - -3)
= 3/2.
So AB and CD can be shown to be parallel.
Similarly the lines BC and AD are parallel.
So the figure is a parallelogram
Finding the perimeter (counting the units between the points):
Perimeter = 2AB + 2BC
By Pythagoras:
AB = sqrt (6^2 + 4^2) = sqrt 52
BC = sqrt (3^2 + 2^2) = sqrt 13
So Perimeter = 2sqrt52 + 2sqrt13
= 4sqrt13 + 2 sqrt13
= 6sqrt13
or 21.63 unit^2 to 2 decimal places.
Area = sqrt52 * perpendicular distance between the lines AB and CD.
