Answer:
Vertex (-2.5,-300)
Step-by-step explanation:
We are given with h(t)=-16 t^2 +80 t. We are asked to find the vertex.
X-coordinate of vertex =
Where 'a' is coefficient of
term
'b' is coefficient of 't' term.
From given function, a= -16
b=80
So,
x-coordinate of vertex =
=-2.5
y-coordinate of vertex =
Simplify it,
=-100 -200
= -300
So, vertex is at (-2.5, -300).
I am sorry, I would love to help but I am not sure. Good luck anyways. :(
Your camera is not faster than ur friends the difference is 0.015
Cos(x°) = (√3)/2
cos⁻¹[(√3)/2] = x°, that means x° = 30°