3/7= 0.42857143
rounded to the neared thousandth, it is 0.429
Answer:
<h2>A. -2</h2>
Step-by-step explanation:
![\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2](https://tex.z-dn.net/?f=%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3Dad-bc%5C%5C%5C%5C%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%283%29%281%29%2B%28-5%29%281%29%3D3-5%3D-2)
Answer:
(-1, 19) and (3, -81)
Step-by-step explanation:
f(x) = 2x³ − 6x² − 27x
f'(x) = 6x² − 12x − 27
-9 = 6x² − 12x − 27
0 = 6x² − 12x − 18
0 = x² − 2x − 3
0 = (x + 1) (x − 3)
x = -1 or 3
f(-1) = 19
f(3) = -81
The points are (-1, 19) and (3, -81).
So we are looking for the GCF which is the largest factor that the two numbers have in common, so you would want to circle all of the number that the two have in common. So it would be 2 twos and 2 X's (2,2,x,x). Which is the most numbers that the two have in common.
