Answer:
Well figure it out yourself because you need to not fall asleep in class. It has happened to me before and I had to control myself!!
Step-by-step explanation:
A polynomial of degree n with roots

can be represented as:

, where A is a constant (The same "a" that appears outside the parentheses in the field where you will type the polynomial). In this question, the number of roots is 4, because the degree of f(x) is 4. If a polynomial has only real coefficients, the complex roots appear in pairs of conjugates. So, since

is a zero,

is a zero too. Then, we have the 4 zeros. Hence,

will be in the form:
X - 3 is a factor because p(3) = 0
Answer: S(t(6)) is equivalent
Step-by-step explanation:
I.e,
S(t(6))
=SXtx6
=(st)(6)
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4