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SCORPION-xisa [38]

2 years ago

5

Eli packed 1,920 peanuts into 8 sacks. He packed an equal number of peanuts in each sack. How many peanuts did he pack into each

sack? A) 210 B) 220 C) 230 D) 240

2 answers:

svlad2 [7]2 years ago

8 0

D because one thousand nine hundred twenty divided by 8 equals two hundred and forty

lutik1710 [3]2 years ago

6 0

1920 divided by 8 = 240

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

2 years ago

I need help i don’t know which one is right please help

olga55 [171]

Answer: 12√2

Step-by-step explanation:

This is a 45-45-90 triangle. In this triangle, a and b are equal lengths, therefore hypotenuse, c, is x√2.

Since a and b is 12, c is 12√2.

7 0

3 years ago

A researcher wishes to estimate, with 99% confidence, the population proportion of adults who think the president of their co

scoray [572]

Answer:

a. n=4148

b. n=3909

c. The sample size is smaller if a known proportion from prior study is used. The difference in sample sizes is 239

Step-by-step explanation:

a. For sample where no preliminary estimate is given, the minimum sample size is calculated using the formula:

$n=p(1-p)(\frac{z}{ME})^2$

Where:

$ME=$ Margin of error
$p=$ is the assumed proportion

#Let p=0.5, substitute in the formula to solve for n:

$n=0.5(1-0.5)\times (2.576/0.02)^2\\\\=4147.36\approx 4148$

Hence, the minimum sample size is 4148

b. If given a preliminary estimate p=0.38, we use the same formula but substitute p with the given value:

$n=p(1-p)(z/ME)^2\\\\=0.38(1-0.38)(2.576/0.02)^2\\\\=3908.47\approx3909$

Hence, the minimum sample size is 3909

c. Comparing the sample sizes from a and b:

$n_{0.5}>n_{0.38}\\\\n_{0.5}-n_{0.38}=4148-3909=239$

Hence, the actual sample size is smaller for a known proportion from prior a prior study.

8 0

3 years ago

Given that a:b:c= 20 : 35 : 15, a) simplify a : b:c, b) find a:b,

Furkat [3]

Answer:

a) 4:7:3

b) 4:7 / 20:35

c) 3:7 / 15:35

4 0

1 year ago

andre [41]

I am pretty sure that it is B

6 0

2 years ago