Answer:
P = 499.2 Watt
Step-by-step explanation:
Answer:
Explanation: the ratio 2:4 can be reduced to 1:2, where the number of girls corresponds to the 1 and the number of boys corresponds to the 2. If there are 14 girls, then there must be 28 boys (14 x 2 = 28). Now to get the total number we need to add the total number of boys and girls together. So 14 + 28 = 42
Step-by-step explanation:
Given:
The graph of a downward parabola.
To find:
The domain and range of the graph.
Solution:
Domain is the set of x-values or input values and range is the set of y-values or output values.
The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.
Domain = R
Domain = (-∞,∞)
The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.
From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.
Range = All real numbers less than or equal to -4.
Range = (-∞,-4]
Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].
Answer:
y = 0
Step-by-step explanation:
The line y = 0 is cutting your triangle in half with perfect symmetry.
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
