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Veronika [31]
3 years ago
15

Please solve these with the full explained answer

Mathematics
2 answers:
faltersainse [42]3 years ago
4 0

Answer:

The given equation is

4x+10=-26

We add the additive inverse of 10 which is -10 to both sides of the equation to obtain,

4x+10+-10=-26+-10

This gives us,

4x+10-10=-26-10

4x+0=-36

statuscvo [17]3 years ago
3 0

ANSWER TO QUESTION 1


The given equation is

4x+10=-26


We add the additive inverse of 10 which is -10 to both sides of the equation to obtain,

4x+10+-10=-26+-10


This gives us,

4x+10-10=-26-10


4x+0=-36


This further simplifies to  


4x=-36


We divide both sides 4 to obtain,

x=-4


ANSWER TO QUESTION 2


Since we got -4 as answer to question one, the next question to answer is

\frac{x}{3}+10=15


We add the additive inverse of 10 which is -10 to both sides to obtain,


\frac{x}{3}+10+-10=15+-10


This gives us,

\frac{x}{3}+10-10=15-10


This simplifies to


\frac{x}{3}+0=5


\frac{x}{3}=5


We now multiply both sides of the equation by 3 to obtain,


3\times \frac{x}{3}=5\times3

This implies that,

x=15


ANSWER TO QUESTION 3


The next equation is 9-2x=35


We add the additive inverse of 9 which is -9 to both sides of the equation to obtain,

9+-9-2x=35+-9

This gives us,

9-9-2x=35-9


This simplifies to,


-2x=26


We multiply both sides by the reciprocal or the multiplicative inverse of -2 to obtain,

-2x\times (-\frac{1}{2})=26\times(-\frac{1}{2})


This gives us,

x=-13


ANSWER TO QUESTION 4.


The next question is \frac{2}{3}x+15=17


We add the additive inverse of 15 to both sides of the equation to obtain,


\frac{2}{3}x+15+-15=17+-15


This evaluates to


\frac{2}{3}x+0=17-15


This implies that,

\frac{2}{3}x=2


We multiply both sides by the multiplicative inverse or the reciprocal of \frac{2}{3}


This implies that,


x=2\times\frac{3}{2}


x=3


ANSWER TO QUESTION 5

The next question to answer is -5x-10=10.


We add the additive inverse of -10 which is 10 to both sides of the equation to obtain,


-5x-10+10=10+10


This gives us,

-5x=20


We through by -10 to obtain,

x=-4


ANSWER TO QUESTION 6

\frac{3}{4}x-9=27


We add the additive inverse of -9 which is 9 to both sides of the equation to obtain,

\frac{3}{4}x-9+9=27+9


This simplifies to;

\frac{3}{4}x=36


We multiply both sides of the equation by the reciprocal of \frac{3}{4} to obtain,

\frac{3}{4}x \times \frac{4}{3}=36\times \frac{4}{3}


x=36\times \frac{4}{3}


x=12\times 4


x=48


ANSWER TO QUESTION 7


The next question to answer is \frac{1}{2}x+13=9.


We add the additive inverse of 13 which is -13 to both sides of the equation to obtain,


\frac{1}{2}x+13+-13=9+-13


This will evaluate to,


\frac{1}{2}x=-4


We now multiply both sides of the equation by 2 to obtain,

x=-4\times 2

x=-8


ANSWER TO QUESTION 8


The last question to solve now is \frac{x-7}{4}=-2


We first of all multiply both sides of the equation by 4 to obtain,


\frac{x-7}{4} \times 4=-2\times 4


This implies that,


x-7=-8


We now add the additive inverse of -7 which is 7 to both sides of the equation to obtain,

x-7+7=-8+7


This implies that

x=-1































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