Answer would be C.
Why A would be incorrect: 100m^2 is 100m × 100 m. That would be as big as a football field.
Why B would be incorrect: 1cm^2 is 1cm × 1cm. You can use a regular 15 cm to measure a piece of paper with the length of 1cm each side.
Why C would be correct: 1m^2 = 1m × 1m and it is also equals to 60cm × 60 cm. A 1 meter ruler = 60 cm = 4 times of your average 15 cm ruler. So, it is reasonable that a classroom is 10m by 10m in length and breadth.
Why D would be incorrect: The same explanation applies to here as well. Things that can be measured with 1m × 1m is a square table so your classroom can't be that small to fit an average of 30 to 40 students in there.
I hope my explanations were detailed and easy to understand. :)
Answer:
I believe its A.
Step-by-step explanation:
if we look at the equation y = -2x - 1, is already in slope-intercept form, therefore, 
has a slope of -2.
now, parallel lines have exactly equal slopes, therefore a parallel to that one above, will have also a slope of -2, so we're really looking for a line whose slope is -2 and runs through -1, 7.
![\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad \qquad \qquad slope = m\implies -2\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-7=-2[x-(-1)]\\\\\\y-7=-2(x+1)\implies y-7=-2x-2\implies y=-2x+5](https://tex.z-dn.net/?f=%20%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B7%7D%29%5Cqquad%20%5Cqquad%20%5Cqquad%20slope%20%3D%20%20m%5Cimplies%20-2%5C%5C%5C%5C%5C%5C%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-7%3D-2%5Bx-%28-1%29%5D%5C%5C%5C%5C%5C%5Cy-7%3D-2%28x%2B1%29%5Cimplies%20y-7%3D-2x-2%5Cimplies%20y%3D-2x%2B5%20)
Answer:
32
Step-by-step explanation:
Suppose Alvin is x years old. Then Elga is x+15 years old.
x+x+15=49
2x=34
x=17
17+15=32
Answer: The submarine would be 710 feet below the surface after it is finished diving.
Step-by-step explanation:
Given: Each move downward was of 355 feet
If the submarine dives below the surface, heading downward in two moves.
Then, the total distance moved by submarine = 2 (355) feet
= 710 feet
Therefore, the submarine would be 710 feet below the surface after it is finished diving.
