Easy
ok, so
for y=a(x-h)^2+k
the vertex is (h,k)
given that the the vertex is (-2,-20)
y=a(x-(-2))^2+(-20)
y=a(x+2)^2-20
find a
when x=0, then y=-12
-12=a(0+2)^2-20
-12=a(2)^2-20
8=4a
2=a
equation is
y=2(x+2)^2-20
if the last term is positive, then maybe y=2(x+2)^2+(-20)?
unless you typed something wrong, then you are right that the last term is -20
Answer:
Hey there!
(2x³) (x⁴)² / 8x¹¹
2x^3(x^8)/8x^11
2x^11/8x^11
1/4
Let me know if this helps :)
Answer:
It would possibly be 6/10
Step-by-step explanation:
hope i had it right
Correct answer is C..................
