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3 years ago

8

Please Answer Correctly To Get Brainliest. Wrong Answers WILL BE REPORTED.

1 answer:

frozen [14]3 years ago

7 0

10 is a real, rational, integer, whole and natural number.
5/6 is a rational number
24 square rooted is irrational number
0 is a real, rational, integer, whole and natural number
- 81 square rooted is a real, rational, integer, whole, and natural number.
I tried. Hope it’s right and hope it helped!

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Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +

nevsk [136]

Answer:

$x_2 \approx -1.769$

Step-by-step explanation:

Let $f(x)=x^3+x+7$

So $f'(x)=3x^2+1$

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

Let $x_1=-2$

We are going to find $x_2$

So we are evaluating $-2-\frac{f(-2)}{f'(-2)}$

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

$f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3$

$f'(-2)=3(-2)^2+1=3(4)+1=12+1=13$

So

$x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769$

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3 years ago

If your smart please help me answer this question .

diamong [38]

Answer:

it should be 30 or something I'm pretty sure that's the answer

8 0

3 years ago

Solve the inequality-7x>21.what is the graph of the solution?

uranmaximum [27]

-7x>21
divide both sides by -7

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3 years ago

How do you know if x is on the rhs or the lhs?

olga nikolaevna [1]

Answer:

Step-by-step explanation:

RHS means on the right hand side

And LHS means on the left hand side

So if x is one the right side of the expression ,it is on the RHS and if it is on the left side of the expression , it is on the LHS

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3 years ago

Find the equation of the line that is perpendicular to y=-2x-9 and contains the points (8,-4)

avanturin [10]

The slope of the given line is -2, and since perpendicular lines have negative reciprocal slopes, the slope of the line we want to find is 1/2.

Substituting into point-slope form,

$y+4=\frac{1}{2}(x-8)\\\\y+4=\frac{1}{2}x-4\\\\\boxed{y=\frac{1}{2}x-8}$

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1 year ago