PLEASE HELP WILL GIVE BRAINLIEsT

Draw a line of fit using (15,25) and (5,35)

seropon [69]

Answer:

your right

Step-by-step explanation:

you had it right nothing to do

8 0

3 years ago

Pls help <br> see the attachments

Nadusha1986 [10]

Answer:

i cant see them can u re upload so i can figure out

Step-by-step explanation:

8 0

3 years ago

Martha cut a whole piece of rope into 8 equal sections. The piece of rope was 36 feet long before she cut it. Whatis the legth i

gogolik [260]

Answer:

4.5

Step-by-step explanation:

all you really need to do for this question is 36/8 and once you solve it or even look it up then the answer shows you 4.5. 4.5*8 is also 36 if you needed to check you answer on a quiz, test or even homework :)

hope this helps

5 0

3 years ago

Technetium-99m is used as a radioactive tracer for certain medical tests. It has a half-life of 1 day. Consider the function T w

Alinara [238K]

Answer:

The expression that represents the number of days until only 10% remains is T((d) 10 %) =100× $(\frac{1}{2} )^{3.322}$ .

Step-by-step explanation:

The equation for half life is of the form

A = A₀× $(\frac{1}{2} )^{\frac{t}{h} }$ .........................................................................(1)

Where

A = Final amount

A₀ = Initial amount

t = Time

h = Half life

For the equation T(d) = 100×2⁽⁻²⁾....................................(2)

We have by comparison with the equation for half life

2 ≡ $\frac{t}{h}$ and and the equation (2) can be written as

Percentage remaining after 2 half lives is

$\frac{A}{A_0}$ ×100=100× $(\frac{1}{2} )^{2 }$

However if the half life of Technetium-99m is 6 hours then we have for one day

$\frac{A}{A_0}$ ×100=100× $(\frac{1}{2} )^{2 *2}$

Therefore an expression that represents the number of days until only 10% remains is

$\frac{A}{A_0}$ ×100=100× $(\frac{1}{2} )^{\frac{d}{h} }$ = 10 %

$(\frac{1}{2} )^{\frac{d}{h} }$ = $\frac{1}{10}$

= ㏑ $(\frac{1}{2} )^{\frac{d}{h} }$ = ㏑( $\frac{1}{10}$ )

= $\frac{d}{h}$ ×㏑ $(\frac{1}{2} )$ = ㏑( $\frac{1}{10}$ )

$\frac{d}{h}$ = $\frac{ln(\frac{1}{10}) }{ln(\frac{1}{2} )}$ = 3.322

Therefore the expression for the number of days 10 % of Technetium-99m will be remaining is

T((d) 10 %) =100× $(\frac{1}{2} )^{3.322}$

3 0

4 years ago

Solve this equation by elimination method...

Snowcat [4.5K]

Answer:

x=2,y=-3

Step-by-step explanation:

detailed explanation showed in the image above

4 0

3 years ago