Question

The product of 6g2 and -2g3 is equals to​

Answer 1

Answer:

We conclude that:

$\left(6g^2\:\right)\times \left(-2g^3\right)=-12g^5$            

Step-by-step explanation:

Given

• 6g²

• -2g³

The product of 6g² and -2g³ can be determined by multiplying each other such as:

$(6g^2\:)\times \:(-2g^3)$

Apply the rule:  a(-b) = -ab

$\left(6g^2\:\right)\times \left(-2g^3\right)=-6g^2\times \:\:2g^3$

Apply exponent rule:   $a^b\times \:a^c=a^{b+c}$

                          $=-6g^{2+3}\times \:2$

                          $=-6g^5\times \:2$

                          $=-12g^5$

Therefore, we conclude that:

$\left(6g^2\:\right)\times \left(-2g^3\right)=-12g^5$