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Alex
3 years ago
9

Solving trigonometric equations

Mathematics
1 answer:
Rufina [12.5K]3 years ago
8 0
Have funnnnnnnnnnnnn
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Are the lines parallel, perpendicular, or neither? One line through the points (3, 2) and (6, 8), and another line through the p
Temka [501]

Answer:

Parallel.

Step-by-step explanation:

Let's find the slope of each line.

One through the points (3,2) and (6,8):-

Slope = rise / run = (8-2)/(6-3)

=  6/3 = 2

The other line:-

Slope =  (6-2)(2-0)

= 4/2 = 2

The slopes are the same so the 2 lines are parallel.

3 0
3 years ago
Read 2 more answers
Match the equation with its corresponding solution for x.
Fudgin [204]

To solve for x, you need to isolate/get the variable "x" by itself in the equation:

3x - 3(x + 1) = 3     Distribute/multiply -3 into (x + 1)

3x + (-3)x + (-3)1 = 3

3x - 3x + 1 = 3

1 = 3

Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3

4 0
3 years ago
A pilot took 1/2 hours to complete his 1/3 pf his ttip how much longer will it take him to complete his trip?
Norma-Jean [14]

Answer:

1.5 hours

Step-by-step explanation:

1/2 + 1/2 + 1/2 =1.5

7 0
2 years ago
I need help with reason number 3
damaskus [11]

Answer:

they are corresponding angles

6 0
3 years ago
helene was paid a total of $33.00 for the 6 hours she worked. she continues to be paid at the same rate. how long would it take
natita [175]

The number of hours that helena need to work to generate 165 dollars is

33 hours.

Helena has to work hours to earn $165. 33

Algebraic equations are equations with

unknown variables. The alphabet letters are used to represent algebraic equations.

Total $33.00 in her 6 hours she worked.

This question should find out how long it takes her to earn her $165.00 in that job.

let x hours be required work hours to earn $165.00 ..

This can be expressed in algebraic equations as:

x= 6× 165/33

x= 990/33

x= 30

Hence, helna have to work thirty hours to earn $165.00 ..

To learn more about Work time problem solving, refer:

brainly.com/question/15447610

#SPJ4

7 0
1 year ago
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