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9966 [12]
3 years ago
6

Plz help asap

Mathematics
2 answers:
PIT_PIT [208]3 years ago
5 0
Phagocytosis is a type of endocytosis, a process through which a cell consumes material by engulfing it with its membrane. Phagocytosis is the engulfing of large particles, such as entire cells.

I would say B
Allisa [31]3 years ago
4 0

A form of passive transport in which the cell membrane surrounds a particle

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If F(x) = log 5 2x, find F^-1(x). a. 5^y=2x b. 5^2y=x c. y = (5^x)/2
gregori [183]

Answer:

y = \frac{5^{x} }{2}

Step-by-step explanation:

y = log 5 2x

inverse ------> y=x

x = log 5 2y

5^{x} = 2y

y = \frac{5^{x} }{2}

4 0
3 years ago
What is the answer to number 23 ?
Vera_Pavlovna [14]

Answer:

C

Step-by-step explanation:

Use πr²

7 0
3 years ago
Read 2 more answers
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
Which of the following theorems verifies that ABC~WXY?
Flura [38]

Answer:

ABC~WXY by AA

Step-by-step explanation:

In ΔABC

∠B = 90°

∠A = 27°

To Find ∠C

Angle sum property: The sum of all angles of triangle is 180°

∠A+∠B+∠C=180°

27°+90°+∠C=180°

∠C=180°-117°

∠C=63°

In ΔWXY

∠X = 90°

∠Y = 63°

We will use angle sum property

So, ∠W+∠Y+∠X=180°

90°+63°+∠W=180°

∠W=180°-(90°+63°)

∠W=27°

So, ∠A=∠W

∠B =∠X

∠C = ∠Y

So, ABC~WXY by Angle - Angle property.

Hence ABC~WXY by AA

3 0
3 years ago
X intercept<br> Of v^2 +5v+6=0
postnew [5]

Answer:

<h2>x-intercepts:</h2><h2>x = -2 and x = -3 ⇒ (-2, 0) and (-3, 0).</h2>

Step-by-step explanation:

f(v)=v^2+5v+6\\\\\text{The x-intercept is for y = 0.}\\\\v^2+5v+6=0\\\\v^2+2v+3v+6=0\\\\v(v+2)+3(v+2)=0\\\\(v+2)(v+3)=0\iff v+2=0\ \vee\ v+3=0\\\\v+2=0\qquad\text{subtract 2 from both sides}\\v=-2\\\\v+3=0\qquad\text{subtract 3 from both sides}\\v=-3

3 0
3 years ago
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