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Montano1993 [528]
3 years ago
9

Circle O is shown. Tangents X Z and Y Z intersect at point Z outside of the circle. The first arc formed is arc b, and the secon

d arc formed is arc a.
Which equation is correct regarding the diagram of circle O?

m∠XZY = One-half(a + b)
m∠XZY = One-half(a – b)
m∠XOY = One-half(a + b)
m∠XOY = One-half(a – b)
Mathematics
2 answers:
Elis [28]3 years ago
5 0

Answer:

m∠XZY = One-half(a – b)

Step-by-step explanation:

lbvjy [14]3 years ago
4 0

Answer:

m∠XZY = One-half(a – b)

Step-by-step explanation:

m∠XZY = One-half(a – b)

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Inverse variation ?
Nookie1986 [14]
<h2>Answer:</h2>

<u>The pressure will be 176 k Pa</u>

<h2>Step-by-step explanation:</h2>

Boyle's law states that the product of volume and pressure gives us a constant value so we can write the expression as

P1V1 = P2V2

By arranging the equation we get

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4 0
3 years ago
Read 2 more answers
If A denotes some​ event, what does Upper A overbar ​denote? If ​P(A)equals0.999​, what is the value of ​P(Upper A overbar​)? Wh
meriva

Answer:

<h3>The event P(\overline{A}) denotes the complement of event A.</h3><h3>The value of P(\overline{A}) is 0.001</h3>

Step-by-step explanation:

Given that A denotes some event .

And also given that P(A)=0.999

<h3>To find the value of P(\overline{A}) :</h3>

Here the event P(\overline{A}) denotes the complement of event A Therefore P(\overline{A}) contains all the events that does not occur in A.

We know that the total probability is 1

So we have that

P(A)+P(\overline{A})=1

P(\overline{A})=1 -P(A)

=1-0.999

=0.001

Hence the complement of event A is P(\overline{A})=0.001

<h3>Therefore the value is P(\overline{A})=0.001</h3>

6 0
3 years ago
NEED HELP ASAP!! I'm doing trigonometry and I've been stuck on this problem I don't really understand it, if you could help that
Tems11 [23]

Answer:

6.1

Step-by-step explanation:

Draw a picture of an equilateral triangle.  Cut the triangle in half, so that you get two 30-60-90 triangles.  The area of these smaller triangles is 8 square inches.

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8 = ⅛ s²√3

64 = s²√3

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s ≈ 6.1

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