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Andrei [34K]
3 years ago
11

Since there are 6 faces on a die, there is 3/6 or 1/2 chance of rolling a die and getting an odd number. Is this empirical or th

eoretical?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0

The statement “since there are 6 faces on a die, there is 3/6 or 1/2 chance of rolling a die and getting an odd number” is theoretical. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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A coordinate map of the local grocery store is shown below. Ice cream is located at the point (-8,0)(−8,0)left parenthesis, minu
Alona [7]

Answer:

Step-by-step explanation:

If on the coordinate map, ice cream is located at the point (-8,0) and sprinkles are located at the point (-8,6), we can find the distance between the coordinate points using the formula;

D = √(x2-x1)²+(y2-y1)²

Given

x1 = -8, y1 = 0, x2 = -8 and y2 = 6

Substitute

D = √(x2-x1)²+(y2-y1)²

D = √(-8-(-8))²+(6-0)²

D = √0²+6²

D = √36

D = 6units

Hence the distance between the coordinate points is 6units

7 0
3 years ago
Solve for t<br><br><br>t - 3= −1
frutty [35]

Answer:

t = 2

Step-by-step explanation:

have a nice day:)

7 0
3 years ago
I need help on this one asap pliz
Doss [256]
C(5,4)(.40)^4(1-.40)^1=5(.4)^4(.6)^1=0.0768

That's 7.68% = 7.7% (rounded)

Note: C(5, 4) is the number of combinations of 5 things taken 4 at a time. You may have seen this written as _5C_4

In general, C(n,r)=\frac{n!}{r!(n-r)!}
8 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin
vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

F =450N

x_1 = 30cm

x_2 = 60cm

Required

The work done

First, we calculate the spring constant (k)

F = kx_1

450N = k *30cm

k = \frac{450N}{30cm}

k =15N/cm

So:

F = kx_1

F(x) = 15x

The work done using Hooke's law is:

W =\int\limits^a_b {F(x)} \, dx

This gives:

W =\int\limits^{60}_{30} {15x} \, dx

Rewrite as:

W =15\int\limits^{60}_{30} {x} \, dx

Integrate

W =15 \frac{x^2}{2}|\limits^{60}_{30}

This gives:

W =15 *\frac{60^2 - 30^2}{2}

W =15 *\frac{2700}{2}

W =15 *1350

W =20250N-cm

Convert to Nm

W =\frac{20250Nm}{100}

W =202.50Nm

7 0
3 years ago
Isla was researching kiwi birds. She categorized each bird she observed by species and gender. The two-way frequency table below
Ludmilka [50]

Answer:

A.

I hope it helps

8 0
3 years ago
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