Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:
r = 2m, l = 15m, d = 4m
Lateral Surface Area of a cone = πrl
= 3.14 x 2 x 15
= 6.28 x 15
= 94.2
= 94 sq. m (After rounding to the nearest)
Hope this helps you!
Answer:
I mean you could do 2(6x+3)
Answer:
This is confusing.. so all ill say involving 2 and 4.
2 x 4 = 8
2 + 4 = 6
2 - 4 = 2
2 dived by 4 = 2
Decimal form:
2.4 or 4.2
Fraction form:
2/4 or 4/2
7/16 = 3.5/8
3.5/8 * 3/3 = 10.5/24
