Hello!
So we have (x^2+4)^2+32=12x^2+48 and initial condition of a=x^2+4 and want it rewritten in terms of a and set equal to zero. So we have;
a^2+32=12(x^2+4) so now we have;
a^2+32=12a so now we just get everything on one side to set equal to zero;
a^2 -12a +32=0 is the final answer.
Hope this helps! Any questions please ask! Thank you so much!
I’m pretty sure it is 66 since the base would be congruent to the top so plug in 7 into 10u-4 and u get 66!! (You plug in 7 since u=7)
Answer:
The function goes to positive infinity as x approaches positive and negative infinity
Step-by-step explanation:
Hey there!!!
Remember :
===> n⁻ˣ is equal to 1 / nˣ
In the question, it is stated n as 6 and x is 3
====> 6⁻³
... 1 / 6³
= 1 / 216
Hope my answer helps!
The new mixture is acquired from the sum of the concentration divided by the total number of gallons. Or we could write it like this.
mix =
![\cfrac{\text{concentrate} \times gallons+\text{concentrate} \times gallons}{\text{the total number of gallons}}](https://tex.z-dn.net/?f=%20%5Ccfrac%7B%5Ctext%7Bconcentrate%7D%20%5Ctimes%20gallons%2B%5Ctext%7Bconcentrate%7D%20%5Ctimes%20gallons%7D%7B%5Ctext%7Bthe%20total%20number%20of%20gallons%7D%7D%20)
Input the numbers
mix =
![\cfrac{50 \% \times 3+30 \% \times 9}{3+9}](https://tex.z-dn.net/?f=%20%5Ccfrac%7B50%20%5C%25%20%5Ctimes%203%2B30%20%5C%25%20%5Ctimes%209%7D%7B3%2B9%7D%20)
simplify the dividend and divisor
mix =
![\cfrac{150 \%+270 \%}{12}](https://tex.z-dn.net/?f=%20%5Ccfrac%7B150%20%5C%25%2B270%20%5C%25%7D%7B12%7D%20)
mix =
![\cfrac{420 \%}{12}](https://tex.z-dn.net/?f=%20%5Ccfrac%7B420%20%5C%25%7D%7B12%7D%20)
mix =
![\cfrac{420 \%}{12}](https://tex.z-dn.net/?f=%20%5Ccfrac%7B420%20%5C%25%7D%7B12%7D%20)
mix = 35%
The new concentration is 35%